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Llana [10]
3 years ago
8

En 4 días un hombre recorrió 120 km. Si cada día avanzó 1/3 de lo que anduvo el día anterior, en el segundo día recorrió.

Mathematics
1 answer:
ioda3 years ago
3 0

Answer:

36 Km

Step-by-step explanation:

Por favor, encontrar el archivo adjunto

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Patrick paid $12 for<br> 25 pounds of candy.<br> How much did each<br> pound of candy cost?
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$12/25 pounds

12/25= $0.48

$0.48/pound is your answer
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The length of a rectangle is 4 more than it's width. Write an equation that will determine the dimensions if the area of the rec
Firdavs [7]

Answer: The equation is W^2 + 4W - 96= 0

{Please note that ^2 means raised to the power of 2}

Step-by-step explanation: We have been given hints as to the measurement of the length and width of the rectangle. The length is given as four more than the width. What that means is that whatever is the width, we simply add four to get the measurement of the length. Therefore if the width is W, then the length is W + 4.

That is,

L = W + 4 and

W = W

Also we have the area given as 96.

Remember that the area of a rectangle is given as

Area = L x W.

In this question, the Area is expressed as

Area = (W + 4) x W

96 = W^2 + 4W

Subtract 96 from both sides of the equation and we have

W^2 + 4W - 96 = 0.

We now have a quadratic equation from which we can determine the dimensions of the rectangle

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Can someone help me?! I don’t understand how to do these problems
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Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
2 years ago
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