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xenn [34]
3 years ago
9

* 70% had the cold lunch prepared by Mr. Femi

Mathematics
1 answer:
MissTica3 years ago
3 0

Answer:

Step-by-step explanation  i dont know what it is cuz im not in ur class

so figure it out

You might be interested in
The first two terms of an arithmetic sequence are 7 and 4. Find the 7th term.
kobusy [5.1K]

EXPLANATION

If the first two terms of an arithmetic sequence are 7 and 4, then we know that an arithmetic sequence has a constant difference d and is defined by

a_n=a_1+(n+1)d

Check wheter the difference is constant:

Compute the differences of all the adjacent terms:

d=a_{n+1}-a_n

Replacing terms:

4-7 = -3

The difference between all of the adjacent terms is the same and equal to

d = -3

The first element of the sequence is

a_1=7a_n=a_1+(n+1)d

Therefore, the nth term is computed by

d= -3

a_n=7+\text{ (n-1)}\cdot(-3)

Refine

d= -3 ,

a_n=-3n+10

Now, replacing n=7

a_7=-3\cdot7+10\text{ = -11}

So, the answer is -11.

8 0
1 year ago
Factor.<br> 4z² – 8z - 5
Nataly [62]

Answer: z = -1/2 = -0.500

z = 5/2 = 2.500

Step-by-step explanation:

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 (22z2 -  8z) -  5  = 0  

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  4z2-8z-5  

The first term is,  4z2  its coefficient is  4 .

The middle term is,  -8z  its coefficient is  -8 .

The last term, "the constant", is  -5  

Step-1 : Multiply the coefficient of the first term by the constant   4 • -5 = -20  

Step-2 : Find two factors of  -20  whose sum equals the coefficient of the middle term, which is   -8 .

     -20    +    1    =    -19  

     -10    +    2    =    -8    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -10  and  2  

                    4z2 - 10z + 2z - 5

Step-4 : Add up the first 2 terms, pulling out like factors :

                   2z • (2z-5)

             Add up the last 2 terms, pulling out common factors :

                    1 • (2z-5)

Step-5 : Add up the four terms of step 4 :

                   (2z+1)  •  (2z-5)

            Which is the desired factorization

Equation at the end of step  2  :

 (2z - 5) • (2z + 1)  = 0  

Step  3  :

Theory - Roots of a product :

3.1    A product of several terms equals zero.  

When a product of two or more terms equals zero, then at least one of the terms must be zero.  

We shall now solve each term = 0 separately  

In other words, we are going to solve as many equations as there are terms in the product  

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

3.2      Solve  :    2z-5 = 0  

Add  5  to both sides of the equation :  

                     2z = 5

Divide both sides of the equation by 2:

                    z = 5/2 = 2.500

Solving a Single Variable Equation :

3.3      Solve  :    2z+1 = 0  

Subtract  1  from both sides of the equation :  

                     2z = -1

Divide both sides of the equation by 2:

                    z = -1/2 = -0.500

Supplement : Solving Quadratic Equation Directly

Solving    4z2-8z-5  = 0   directly  

Earlier we factored this polynomial by splitting the middle term. let us now solve the equation by Completing The Square and by using the Quadratic Formula

Parabola, Finding the Vertex :

4.1      Find the Vertex of   y = 4z2-8z-5

For any parabola,Az2+Bz+C,the  z -coordinate of the vertex is given by  -B/(2A) . In our case the  z  coordinate is   1.0000  

Plugging into the parabola formula   1.0000  for  z  we can calculate the  y -coordinate :  

 y = 4.0 * 1.00 * 1.00 - 8.0 * 1.00 - 5.0

or   y = -9.000

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = 4z2-8z-5

Axis of Symmetry (dashed)  {z}={ 1.00}  

Vertex at  {z,y} = { 1.00,-9.00}  

z -Intercepts (Roots) :

Root 1 at  {z,y} = {-0.50, 0.00}  

Root 2 at  {z,y} = { 2.50, 0.00}  

Solve Quadratic Equation by Completing The Square

4.2     Solving   4z2-8z-5 = 0 by Completing The Square .

Divide both sides of the equation by  4  to have 1 as the coefficient of the first term :

  z2-2z-(5/4) = 0

Add  5/4  to both side of the equation :

  z2-2z = 5/4

Now the clever bit: Take the coefficient of  z , which is  2 , divide by two, giving  1 , and finally square it giving  1  

Add  1  to both sides of the equation :

 On the right hand side we have :

  5/4  +  1    or,  (5/4)+(1/1)  

 The common denominator of the two fractions is  4   Adding  (5/4)+(4/4)  gives  9/4  

 So adding to both sides we finally get :

  z2-2z+1 = 9/4

Adding  1  has completed the left hand side into a perfect square :

  z2-2z+1  =

  (z-1) • (z-1)  =

 (z-1)2

Things which are equal to the same thing are also equal to one another. Since

  z2-2z+1 = 9/4 and

  z2-2z+1 = (z-1)2

then, according to the law of transitivity,

  (z-1)2 = 9/4

We'll refer to this Equation as  Eq. #4.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (z-1)2   is

  (z-1)2/2 =

 (z-1)1 =

  z-1

Now, applying the Square Root Principle to  Eq. #4.2.1  we get:

  z-1 = √ 9/4

Add  1  to both sides to obtain:

  z = 1 + √ 9/4

Since a square root has two values, one positive and the other negative

  z2 - 2z - (5/4) = 0

  has two solutions:

 z = 1 + √ 9/4

  or

 z = 1 - √ 9/4

Note that  √ 9/4 can be written as

 √ 9  / √ 4   which is 3 / 2

Solve Quadratic Equation using the Quadratic Formula

4.3     Solving    4z2-8z-5 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  z  , the solution for   Az2+Bz+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

           - B  ±  √ B2-4AC

 z =   ————————

                     2A

 In our case,  A   =     4

                     B   =    -8

                     C   =   -5

Accordingly,  B2  -  4AC   =

                    64 - (-80) =

                    144

Applying the quadratic formula :

              8 ± √ 144

  z  =    —————

                   8

Can  √ 144 be simplified ?

Yes!   The prime factorization of  144   is

  2•2•2•2•3•3  

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 144   =  √ 2•2•2•2•3•3   =2•2•3•√ 1   =

               ±  12 • √ 1   =

               ±  12

So now we are looking at:

          z  =  ( 8 ± 12) / 8

Two real solutions:

z =(8+√144)/8=1+3/2= 2.500

or:

z =(8-√144)/8=1-3/2= -0.500

Two solutions were found :

z = -1/2 = -0.500

z = 5/2 = 2.500

3 0
3 years ago
Read 2 more answers
Can someone help me solve #1 and #2 by working backward? Here is a picture:
Brilliant_brown [7]
1. 4(n+3)=16, n+3=4, n=1
2. m/4+3=24, m/4=21, m=84
1. three added to a number n implies n+3, 4 times that sum is 4 (n+3), to solve divide both sides by 4 then subtract three from both sides.
2. a number divided by 4 means n/4 adding it to three n/4+3, to solve subtract 3 from both sides then multiply both sides by 4
3 0
3 years ago
What is the solution to this system of equations?
Ede4ka [16]

Answer:

First choice.

Step-by-step explanation:

You could plug in the choices to see which would make all the 3 equations true.

Let's start with (x=2,y=-6,z=1):

2x+y-z=-3

2(2)+-6-1=-3

4-6-1=-3

-2-1=-3

-3=-3 is true so the first choice satisfies the first equation.

5x-2y+2z=24

5(2)-2(-6)+2(1)=24

10+12+2=24

24=24 is true so the first choice satisfies the second equation.

3x-z=5

3(2)-1=5

6-1=5

5=5 is true so the first choice satisfies the third equation.

We don't have to go any further since we found the solution.

---------Another way.

Multiply the first equation by 2 and add equation 1 and equation 2  together.

2(2x+y-z=-3)

4x+2y-2z=-6 is the first equation multiplied by 2.

5x-2y+2z=24

----------------------Add the equations together:

9x+0+0=18

9x=18

Divide both sides by 9:

x=18/9

x=2

Using the third equation along with x=2 we can find z.

3x-z=5 with x=2:

3(2)-z=5

6-z=5

Add z on both sides:

6=5+z

Subtract 5 on both sides:

1=z

Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:

2(2)+y-1=-3

4+y-1=-3

3+y=-3

Subtract 3 on both sides:

y=-6

So the solution is (x=2,y=-6,z=1).

8 0
3 years ago
I will give Brainliest its maths and I need help on a b and c
JulsSmile [24]

Answer:

{5}^{3}  \times  {5}^{x}  =  {5}^{7}  \\ 3 + x = 7 \\ x = 4

( {q}^{2} )^{y}  =  {q}^{6}  \\ 2y = 6 \\ y = 3

{1000}^{m}  \div  {100}^{n} =  {10}^{z}   \\  \frac{1000 ^{m} }{ {100}^{n} }  =  {10}^{z}  \\   \\ {10}^{m - n}  =  {10}^{z}

Can I have the brainliest please?

4 0
3 years ago
Read 2 more answers
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