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3 years ago

11

What is the gradient of the blue line

1 answer:

d1i1m1o1n [39]3 years ago

6 0

Answer:

1/4

Step-by-step explanation:

1) Find two points of the line

(4,2) and (8,3)

Gradient = (y2 - y1)/(x2-x1)

(3-2)/(8-4) = 1/4

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Fill in the blank and dropdown menus to form a true statement below.

Pavlova-9 [17]

Answer:

It's polyhedron, not polygon

Because above figure has merely 10 sides.

so the polyhedron above has 10 sides, each of them has 20°.

so total degree in polyhedron is > 180(n-2)

>180(10-2)

> 180×8

> 1440

Step-by-step explanation:

Hope it helps you

5 0

3 years ago

Which is a solution to 2x squared -7 x= 3 ?

vovikov84 [41]

Your answer would be A:x=3

6 0

4 years ago

Which of the following is not equal to sin⁡(-230°)?

xenn [34]

From trigonometry we know that:

if $sin(\theta)=sin(\alpha)$

then, $\theta=n\pi+(-1)^n\alpha$ (where $n$ is an integer)

This can be rewritten in degrees as:

$\theta=n(180^{\circ})+(-1)^n\alpha$ .............(Equation 1)

Now, in our case, $\alpha=-230^{\circ}$

Therefore, (Equation 1) can be written as:

$\theta=n(180^{\circ})+(-1)^n(-230^{\circ})$ ..........(Equation 2)

Now, to find the correct options all that we have to do is replace n by relevant integers and find the values of $\theta$ that match.

For n=2, (Equation 2) gives us: $\theta=2\times 180^{\circ}+(-1)^2(-230^{\circ})=360^{\circ}-230^{\circ}=130^{\circ}$ .

Thus, $sin(230^{\circ})=sin(130^{\circ})$

Now, we know that: $-sin(-50^{\circ})=sin(50^{\circ})$

Let n=-1, then:

$\theta=(-1)\times 180^{\circ}+(-1)^{-1}(-230^{\circ})=-180^{\circ}+230^{\circ}=50^{\circ}$

Thus, $sin(-230^{\circ})=-sin(-50^{\circ})$

Likewise, $sin(-230^{\circ})=sin(50^{\circ})$

Only the last option $sin(-50^{\circ})$ will never match $sin(-230^{\circ})$ because no integral value of $n$ will ever give $\theta=-50^{\circ}$

Thus the last option is the correct option.

3 0

3 years ago

Read 2 more answers

Can somebody help me on these two

Zarrin [17]

to find the slope for the first one, use the formula $\frac{y2-y1}{x2-x1}$

(It's the slope formula)

so... $3=y2, 3=y1, 2=x2, 10=x1$

then plug in... $\frac{3-3}{2-10} =\frac{0}{-8} = 0$

this line has a slope of 0

As for the miles problem, to find mph, the miles have to be at 1.

so... $4x=242\\x=60.5$

therefore, he drove 60.5 mph

6 0

3 years ago

Find factors of 40 that will SUBTRACT to 3 <br><br> Smaller factor:<br> Larger factor:

Cloud [144]

8 and 5 multiply to 40 but subtract to 3.

3 0

3 years ago