Given: AB ⊥ l, B ∈ l, M ∈ AB , AM = 7 in, AB = 15 in. Find the distance between point M and line l.
1 answer:
AB ⊥ l, B ∈ l, M ∈ AB , AM = 7 in, AB = 15 in.
Here AB is a line segment which is perpendicular to line I.
Point B lies on line I,and Point B lies on line segment AB.
⇒AB=15 [Given]
⇒AM+MB=15
⇒AM=7[given]
⇒7+MB=15
⇒MB=15-7
⇒MB=8in
So,the length of line segment MB is 8 in.
The same thing is depicted in the diagram.
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Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:
Now find the area:
We have two of these triangles.
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First we can find the area of the rectangle.
Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.
The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:
Calculate the area:
We have two of these triangles.
Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:
Now find the area:
We have two of these triangles.
Add all the areas together: