Given: AB ⊥ l, B ∈ l, M ∈ AB , AM = 7 in, AB = 15 in. Find the distance between point M and line l.
1 answer:
AB ⊥ l, B ∈ l, M ∈ AB , AM = 7 in, AB = 15 in.
Here AB is a line segment which is perpendicular to line I.
Point B lies on line I,and Point B lies on line segment AB.
⇒AB=15 [Given]
⇒AM+MB=15
⇒AM=7[given]
⇒7+MB=15
⇒MB=15-7
⇒MB=8in
So,the length of line segment MB is 8 in.
The same thing is depicted in the diagram.
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Answer:
Given : ∠ABC is a right angle, ∠D BC is a straight angle.
To prove :∠AB D is a right angle.
Proof: ∠ ABC = 90°[ Given]
∠ D BC= 180° [ D BC is a straight line]
now, ∠ AB D and ∠ AB C are adjacent angles forming linear pair.
∠ AB D +∠ AB C =180° [By linear pair axiom]
⇒∠ AB D + 90= 180°
⇒∠ AB D=180°-90°
⇒∠ AB D=90°
∠AB D is a right angle
Hence proved.
