Given: AB ⊥ l, B ∈ l, M ∈ AB , AM = 7 in, AB = 15 in. Find the distance between point M and line l.
1 answer:
AB ⊥ l, B ∈ l, M ∈ AB , AM = 7 in, AB = 15 in.
Here AB is a line segment which is perpendicular to line I.
Point B lies on line I,and Point B lies on line segment AB.
⇒AB=15 [Given]
⇒AM+MB=15
⇒AM=7[given]
⇒7+MB=15
⇒MB=15-7
⇒MB=8in
So,the length of line segment MB is 8 in.
The same thing is depicted in the diagram.
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Answer:
y=7/3x²-13/3x+2
Step-by-step explanation:
<u>Determine the value of c:</u>
y=ax²+bx+c
2=a(0)²+b(0)+c
2=c
<u>Substitute (1,0) into the quadratic and create an equation with a and b:</u>
y=ax²+bx+2
0=a(1)²+b(1)+2
0=a+b+2
-2=a+b
<u>Do the same with (3,10) to get a second equation:</u>
y=ax²+bx+2
10=a(3)²+b(3)+2
10=9a+3b+2
8=9a+3b
<u>Set the two equations equal to each other and solve for a and b:</u>
-2=a+b
8=9a+3b
<u>Multiply first equation by 3 and eliminate b to find a:</u>
-6=3a+3b
- (8=9a+3b)
_______
-14=-6a
14/6=a
7/3=a
<u>Substitute 7/3=a into the first equation:</u>
-2=7/3+b
-2-(7/3)=b
-13/3=b
<u>Final equation:</u>
y=7/3x²-13/3x+2
See the graph for a visual representation
Radius / diameter as a length cannot be negative, that's why '-16' is wrong.