The quantity of sugar required for 2/4 of the recipe is 1/3 cups
<h3>How to solve fraction?</h3>
let
- x = quantity of sugar needed
Ratio of sugar to recipe
2/3 : 1 = x : 2/4
2/3 ÷ 1 = x ÷ 2/4
2/3 × 1/1 = x × 4/2
2/3 = x × 2
2/3 = 2x
x = 2/3 ÷ 2
x = 2/3 × 1/2
= 2/6
x = 1/3 cups
Therefore, the quantity of sugar required for 2/4 of the recipe is 1/3 cups
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Answer:
19. 11
21. 119
Step-by-step explanation:
19.
(-5)² - [4(-3 ∙ 2 + 4)² + 3] + 5 =
= (-5)² - [4(-6 + 4)² + 3] + 5
= (-5)² - [4(-2)² + 3] + 5
= (-5)² - [4(4) + 3] + 5
= (-5)² - [16 + 3] + 5
= 25 - 19 + 5
= 6 + 5
= 11
21.
5 - 8[6 - (3 ∙ 2 - 8 + 2|4 ÷ -2 + (-3)| - 4) - 7 · 2] - 3² · (-2) =
= 5 - 8[6 - (3 ∙ 2 - 8 + 2|-2 + (-3)| - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (3 ∙ 2 - 8 + 2|-5| - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (3 ∙ 2 - 8 + 2(5) - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (6 - 8 + 10 - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (-2 + 10 - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - (8 - 4) - 7 · 2] - 3² · (-2)
= 5 - 8[6 - 4 - 7 · 2] - 3² · (-2)
= 5 - 8[6 - 4 - 14] - 3² · (-2)
= 5 - 8[2 - 14] - 3² · (-2)
= 5 - 8[-12] - 3² · (-2)
= 5 - (-96) - 9 · (-2)
= 5 + 96 + 18
= 101 + 18
= 119
-1F, 0F, 3F, 5F, 6F Think of this as a normal number line -3 -2 -1 0 1 2 3
hope this helped
I'm really bad at math so can you help me with that
