Answer:
Step-by-step explanation:
h = -6
+20t + 4
I will use calculus, maybe that's not how you're supposed to do this
-12t +20 =0
12t = 20
t = 20 /12
t = 1 
t = 1 
there will be a max at 1.6666666666 seconds
-6*
+ 20 * 1.6666666666 +4
= 16.666666666666 + 33.333333333333 + 4
= - 16
+ 33
+ 4
= 20
feet max height ( not too high, for a rocket)
time of flight:
0 = -6
+20t + 4
use quadratic formula to find t
-20 +- sqrt [
- 4*(-6)*4 ] / 2*(-6)
-20 +- sqrt [400 + 96 ] / -12
-20 +- sqrt [496 ] / -12
-20 +- 22.27105 / -12
try the negative option 1st
-42.27105 / -12
3.522 seconds. time of flight
when will the rocket be at 12' ? :
12 = -6
+20t + 4
0 = -6
+20t -8
use quadratic formula again to find t
-20 +- sqrt [
- 4*(-6)*(-8) ] / 2*(-6)
-20 +- sqrt [ 400 - 192 ] / -12
-20 +- sqrt [208 ] / -12
-20 - 14.4222 / -12
-34.4222 / -12
2.8685 seconds ( on the way down)
and
-20 + 14.4222 / -12
-5.578 / - 12
0.4648 seconds ( on the way up )
In numbers only:
4x + 3 = 6x - 5
C)x = 4
Answer:
1) m=2/9; y-intercept= 17/3
2) m=7 ; y-intercept= 22
3) m= -2/11 ; y-intercept= 100/11
4) m= 13/19 ; y-intercept= -53/13
Step by Step Explanation:
Use the slope formula to find the slope m.
22,000 x 2= 44,000
120%
So I think it would equal to 345,600,0
I am not sure
P.S. I am not good at math sorry if it is wrong...
Answer:
ty for the free points
Step-by-step explanation:
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