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Slav-nsk [51]
3 years ago
5

Find the midpoint of the segment with the end points(1 , 7) and (9, 0)

Mathematics
1 answer:
kompoz [17]3 years ago
8 0

Answer:

(5,3.5)

Step-by-step explanation:

x=(1+9)/2=5

y=(7+0)/2=3.5

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How can the figure below be changed so that it has exactly one lines of symmetry?
frez [133]

Answer:

C

Step-by-step explanation:

By moving point B 1.5 units to the right, you create an icoselles triangle, which has just one line of symmetry

4 0
3 years ago
Which graph represents exponential decay?
xz_007 [3.2K]

Answer:

  (d) -- see attached

Step-by-step explanation:

A graph that shows exponential decay is one that tends toward a horizontal asymptote as x gets large.

__

A basic (parent) exponential decay curve is concave upward and tends toward zero as x gets large. The fractional change in any interval is the same as for any other interval of equal size. The curve attached decreases by a factor of 2 when x increases by 1.

6 0
2 years ago
A spinner has three colors: red, blue, abd yellow. The red and blue sectors are the same size. If you spin twice, the probabilit
givi [52]

Answer:

36%

Step-by-step explanation:

Red and blue is 8%

and= multiply

0.08 unmultiply = 0.64 or 64%

yellow = 100-64= 36%

5 0
3 years ago
Please help me with this i really need help
kifflom [539]

Answer:

70%

Step-by-step explanation:

The number of students with an April birthday and candles is in the upper left, 14. That’s the “part” Percentage is part/whole x 100.

To figure out the “whole”, you need to add up all the students in the first row of the table, because those are the April birthdays. 14 + 6 = 20

14/20 = 0.7 x 100 = 70%

8 0
3 years ago
the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?
Soloha48 [4]

<u>Given</u>:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

<u>General term:</u>

The general term of the geometric sequence is given by

a_n=a(r)^{n-1}

where a is the first term and r is the common ratio.

The 11th term is given is

a_{11}=a(4)^{11-1}

48=a(4)^{10} ------- (1)

The 12th term is given by

192=a(4)^{11} ------- (2)

<u>Value of a:</u>

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

48=a(1048576)

Dividing both sides by 1048576, we get;

\frac{3}{65536}=a

Thus, the value of a is \frac{3}{65536}

<u>Value of the 10th term:</u>

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term a_n=a(r)^{n-1}, we get;

a_{10}=\frac{3}{65536}(4)^{10-1}

a_{10}=\frac{3}{65536}(4)^{9}

a_{10}=\frac{3}{65536}(262144)

a_{10}=\frac{786432}{65536}

a_{10}=12

Thus, the 10th term of the sequence is 12.

8 0
3 years ago
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