Let x be the first computer. Let y be the first computer. We know that Work = 1 / Time.
If the work together, work can be done in 30 seconds. Thus, we have:
1/x + 1/y = 1/30
If x will finish in 50 seconds, we need to compute how many seconds y can finish the same work. Thus solving for y, we have the equation below:
1/50 + 1/y = 1/30
1/y = 1/30 - 1/50
1/y = 1/75
The second computer can finish the same work in 75 seconds.
50 = 85 - 13.254x...... solve for x
x = 2.64071 round up to 3
hence 2001 + 3 = 2004
Answer:
75
Step-by-step explanation:
Let x represent the number of bullfrogs in the population.
We have been given that in a study of the population density of bullfrogs, 25 are captured and marked in the first sampling. Five days later, 30 frogs are captured, 10 of which have marks.
We will use proportion to solve our given problem as:





Therefore, the estimated number of bullfrogs in the population would be 75.