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2 years ago

What is not a multiple of 7

Mathematics

1 answer:

salantis [7]2 years ago

5 0

Answer:

34 is not a mulitple of 7

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Paguei 74,00 por uma bolsa e uma sandália. A bolsa foi 23,00 mais barato q a sandália. Qual o preço da sandália?

alukav5142 [94]

Responda:

48,5

Explicação passo a passo:

Dado que:

Custo total de bolsa e sandália = 74,00

Deixei :

Custo da sandália = x

Custo da bolsa = x - 23

Preço da sandália:

x + (x - 23) = 74

x + x - 23 = 74

2x - 23 = 74

2x = 74 + 23

2x = 97

x = 97/2

x = 48,5

Portanto, custo da sandália, x = 48,5

7 0

2 years ago

8 The circle graph below shows the number of votes each candidate received in a recent student

Kobotan [32]

Answer:

60%

Step-by-step explanation:

7 0

2 years ago

So yeah. . .. idk how to do this

kipiarov [429]

<em>Please </em>use for reference. Merci.

To find rate of change simply divide y/x.

hour 2: 56/2=28

hour 4: 125/4~about 31.3 or 31

hour 5: 164/5=32.8 or ~ 33

hour 8: 271/8 ~ about 34 or 33.875

hour 13: 404/13 ~ about 31 or 31.0769231

What numbers are the largest?

hours 5 and 8

Thus, the correct answer was option C.

5 0

2 years ago

How can we simplify radicals involving negative values?

RSB [31]

Answer:

using imaginary numbers

Step-by-step explanation:

4 0

2 years ago

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

8 0

3 years ago

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