Answer:
The answer is
<h2>
</h2>
Step-by-step explanation:
The distance between two points can be found by using the formula
<h3>
</h3>
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
E(-3,4) and B(-1,6)
The distance between them is
<h3>
</h3>
We have the final answer as
<h3>
</h3>
Hope this helps you
D because y=3x-2
Y+2=3x
Y+2/3=x
Answer:
About 3 times faster
Step-by-step explanation:
Cheetah's speed = 110 km / hr
World 100m sprint record :
Speed of sprinter :
Distance / time
100 m / 9.58s
= 10.438413 m/s
Convert Cheetah's speed to m/s
110 km/hr = (110 * 1000)m / (60 * 60 s)
= 110000 m / 3600 s
= 30.55555 m/s
Number of times cheetah is faster than sprinter :
30.55555 m/s ÷ 10.438413 m/s
= 2.927 times
Answer:
Midpoint (-2,4)
distance nearest tenth = 8.9
The approximate distance = 9
Step-by-step explanation:
Formulas
PQ midpoint = (x2 + x1)/2, (y2 + y1)/2
distance d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )
Givens
x2 = -4
x1 = 0
y2 = 1
y1 = 7
Solution
M(PQ) = (-4+0)/2, (1 + 7)/2
M(PQ) = -2, 4
The midpoint is -2,4
The distance = sqrt( (4 - 0)^2 + (1 + 7)^2 )
The distance = sqrt(16 + 64)
The distance = sqrt(80)
The distance = 4√5 exactly
The distance = 8.94
The distance = 8.9 To the nearest tenth
Question 2
The distance is rounded to the nearest whole number which is 9.
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
