Try this explanation:
1. if to re-write the given function as:
then it is possible to define its range:
2)
![\lim_{x \to+ \infty}[1- \frac{C}{e^x+C}]=1; \\ \lim_{x \to- \infty}[1- \frac{C}{e^x+C}]=0](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%2B%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D1%3B%20%20%5C%5C%20%5Clim_%7Bx%20%5Cto-%20%5Cinfty%7D%5B1-%20%5Cfrac%7BC%7D%7Be%5Ex%2BC%7D%5D%3D0)
answer: (0;1)
Answer:
the answer to the problem is -18
Answer:
x=-11
Step-by-step explanation:
x+8=-3
x=-3-8 :- collect like term
since we are adding two negative numbers, we will let the number be negative but add them.
x=-11
Hope it helps :)
Answer: it will trave 56.89 meters before coming to rest.
Step-by-step explanation:
This is a geometric progression since the distance travelled (height) by the ball is reducing by a constant ratio, r. Since the number of times that the ball will bounce is infinite, then we would apply the formula for determining the sum of the terms in a geometric progression to infinity which is expressed as
S = a/(1 - r)
where
S = sum of the distance travelled by the ball
a = initial distance or height of the ball
r = common ratio
From the information given,
a = 128/9
r = (32/3)/(128/9) = 0.75
Therefore,
S = (128/9)/(1 - 0.75) = 56.89 meters
Answer:
9
±
3
i
√
7 / 2
Step-by-step explanation:
hope this helps
