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irakobra [83]
2 years ago
6

(2 mark) A group of 10 friends are planning to a trip. You are responsible for the flight tickets. You searched on the Internet

and you found a flight with four different classes. Economy class (100$) has only four available seat, First class (150$) has only 2 available seats, Business class (200$) has only 3 available seats, and Premium class (300$) has 5 available seats. Your budget is limited and you want to save as much as you can. In how many ways you book the tickets?​
Mathematics
1 answer:
goblinko [34]2 years ago
4 0

Answer:

4 seats economic, 2 seats first class, 3 seats business class, 1 seat premium class

Step-by-step explanation:

4 \times economy class = 400$ +

2 \times first class = 300$ +

3 \times bussines class = 600$ +

1 \times premium class = 300$

= 1600$

<em>This </em><em>is </em><em>the </em><em>way </em><em>to </em><em>spend </em><em>the </em><em>least </em><em>money </em><em>if </em><em>everyone </em><em>is </em><em>seated </em><em>on </em><em>one </em><em>seat.</em><em> </em>

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A real estate agent has 8 master keys to open several new homes. Only 1 master key will open any given house. If 40% of these ho
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Answer:

Step-by-step explanation:

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Let the probability of selecting a correct key be P(S)

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P(S) = \dfrac{ (^1_1) (^7_2)   }{   ^8_3 }

P(S) = \dfrac{21}{56}

P(S) = 0.375

Finally, for the real estate agent to have access to specific homes supposing the agent select three master keys at random prior to the time he left his office, Then:

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P(F ∪ (G∩S) = P(F) + P(G) × P(S)

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P(F ∪ (G∩S) = 0.40 + 0.225

P(F ∪ (G∩S) =0.625

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2 years ago
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Step-by-step explanation:

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If you hook them together at one end, then there's no way they can reach the ends of the 11cm side.  The farthest they can reach is 10cm.

That's what choice-B says.


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