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3 years ago

Please answer soon!!!!

Mathematics

1 answer:

sweet [91]3 years ago

3 0

Answer:

2 and 5/8 +2 and 2/5

Step-by-step explanation:

That equals 5 1/40

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Svet_ta [14]

Answer: 25

Step-by-step explanation:

The hypothenuse will be gotten by using Pythagoras formula. This will be:

Hypotenuse² = Opposite² + Adjacent²

Hypotenuse²= 7² + 24²

Hypotenuse² = 49 + 576

Hypotenuse² = 625

Hypotenuse = ✓625

Hypotenuse = 25kilometer

4 0

3 years ago

John read half of the time that Tom read. Tom read that half of the time Sasha read. Sasha read twise as long as Mike. If Mike r

deff fn [24]

Answer:

John read for 3 hours

Step-by-step explanation:

j = 0.5t; t = 0.5s; s = 2m; m = 6

s=2(6), s=12; t=0.5(12), t=6; j=0.5(6), j=3

5 0

3 years ago

Read 2 more answers

For the function f(x)=x+4, what is the order pair for the point on the graph when x=3p?

anygoal [31]

Answer: f ( x ) = x + 4

x = 3 p

f ( 3 p ) = 3 p + 4

Answer. D )

The ordered pair is:

( x, y ) = ( 3 p, 3 p + 4 )

PLEASEEEE!!! GIVE ME A BRAINLY!!!!

3 0

4 years ago

Ahab jumped 2 times in 4 minutes. at that rate, how many times would he jump in 9 hours?

jeka57 [31]

Answer: 270

Step-by-step explanation: 20 mins = 10 jumps now 20x3 is 60 which is an hour so in an hour he would have jumped 30 times and if you times 30 with 9 you would get 270 hence your answer

7 0

2 years ago

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$

$\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}$

8 0

2 years ago