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3 years ago

Dan rolls 2 fair dice and adds the results from each. Work out the probability of getting a total less than 3.

Mathematics

1 answer:

agasfer [191]3 years ago

8 0

Answer:

1 / 36

Step-by-step explanation:

A roll of 2 fair dice :

Total number of possible outcomes = n² ; n = number of faces in a dice = 6² = 36

Probability = required outcome / Total possible outcomes

Required outcome = total less than 3 = 1 (from sample space provided)

Hence,

P(total less than 3) = 1/36

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Hey, can someone help me with this?

kvv77 [185]

Answer:

1/2 ÷ 4 = 1/8

Step-by-step explanation:

The way to think about this is you want to divide how much you have by how many people there are.

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4 years ago

G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.

shtirl [24]

BG ≅ AG

BG is the perpendicular to the side of the triangle while AG is the angle bisector , So BG cannot equal AG , So BG cannot be congruent to AG. Hence first is false.

DG ≅ FG

DG And FG both are the perpendicular to the sides from the incentre of the circle , Hence DG and FG are congruent , So second statement is true.

DG ≅ BG

Again DG and BG both are the perpendicular to the sides from the incentre of the circle , Hence DG and BG are congruent , So third statement is true.

GE bisects ∠DEF

As said in the question GE is the angle bisector , So yes GE bisects ∠DEF.

This Statement is true.

GA bisects ∠BAF

Again As said in the question GA is the angle bisector , So yes GA bisects ∠BAF.

Hence 2nd, 3rd , 4th , and 5th options are correct.

6 0

3 years ago

Read 2 more answers

Evaluate: |-5|-|6|+|8|

marin [14]

Answer: 7

Step-by-step explanation:

First find the absolute value of the numbers then apply the signs.

The absolute value of -5 is 5

The absolute value of 6 is 6

The absolute value of 8 is 8

5 - 6 + 8 = 7

8 0

3 years ago

23.

Crazy boy [7]

Answer:

The number that cannot be the largest possible 6-digit number is;

(D) AAABCB

Step-by-step explanation:

From the question, we have;

A, B, and C = Distinct digits, therefore, A ≠ B ≠ C

The number of digits in the number to be formed = 6 digits

The number of 'A' in the number to be formed = 3

The number of 'B' in the number to be formed = 2

The number of 'C' in the number to be formed = 1

We have;

When A > B > C

The largest possible number = AAABBC

When C > A > B

The largest possible number = CAAABB

When B > A > C

The largest possible number = BBAAAC

When A > C > B

The largest possible number = AAACBB

Therefore, given that when A > B > C, the largest possible number = AAABBC, we have;

AAABBC > AAABCB, because B > C, therefore, within the tens and unit of the two 6 digit numbers, we have, BC > CB

∴ AAABBC > AAABCB and <u>AAABCB</u>, cannot be the largest possible 6-digit number

3 0

3 years ago

What is the value of (2/3)^-4

tigry1 [53]

Answer:

5.0625

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers