From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
Answer:
Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( -9 ,-8)
point B( x₂ , y₂ )≡ (-15 ,-16)
To Find:
Slope = ?
Solution:
Slope of Line Segment AB is given as

Substituting the values we get

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Answer:
23.6 or 1 4 × π × 8 = 2 π if its not right let me know
Step-by-step explanation:
The answer is going to be 250
Answer:
C) 3pi>9
Step-by-step explanation: