Use the formula or complete the square.
The zeroes of the quadratic can be real and rational; real and irrational; complex conjugates.
If the quadratic is ax²+bx+c, x=(-b+√b²-4ac)/2a.
If b² > 4ac the solutions are real. If b²-4ac is a perfect square, the solutions are real and rational; otherwise they’re real but irrational.
If b² < 4ac the solutions are complex.
Answer:
A. C=125+5n
B. 30 Months
Step-by-step explanation:
275-125=150÷5=30
Answer:
Hence, the sphere has a radius of 
and is centered at the point (1,-1,1)
Step-by-step explanation:
We have the equation
We have to take into account the relation between coordinates
by substituting we have:
![\rho=2[\frac{x}{\rho}-\frac{y}{\rho}+\frac{z}{\rho}]\\\\\rho^2=2x-2y+2z\\\\x^2+y^2+z^2=2x-2y+2z](https://tex.z-dn.net/?f=%5Crho%3D2%5B%5Cfrac%7Bx%7D%7B%5Crho%7D-%5Cfrac%7By%7D%7B%5Crho%7D%2B%5Cfrac%7Bz%7D%7B%5Crho%7D%5D%5C%5C%5C%5C%5Crho%5E2%3D2x-2y%2B2z%5C%5C%5C%5Cx%5E2%2By%5E2%2Bz%5E2%3D2x-2y%2B2z)
We have to complete squares:
Hence, the sphere has a radius of and is centered at the point (1,-1,1)
hope this helps!!
We have that
the expressions is <span>∑ i=1 to 5 (4i)
for i=1-----------> (4*1)=4
</span>for i=2-----------> (4*2)=8
for i=3-----------> (4*3)=12
for i=4-----------> (4*4)=16
for i=5-----------> (4*5)=20
∑ i=1 to 5 (4i)=[4+8+12+16+20]=60
the answer is 60
