Question

the shorter side of a rectangle is 60% of the longer side and the perimeter of the rectangle is 96 inches. find the side lengths

Answer 1

Answer:

Length of the rectangle:

$x = \frac{4800}{106} = \frac{2400}{53}$

Breadth of the rectangle:

$60\%(x) = \frac{60}{100} \times \frac{4800}{106} \: \: \: \: \: \: \: \: \: \: \: \\ =60 \times \frac{48}{106} \\ = \frac{2880}{106}$

Step-by-step explanation:

Longer side of the rectangle(length) = x

Shorter side of the rectangle(breadth) = (60%)x

Perimeter of the rectangle = 2(l+b) = 96 inches

Hence,

$96 = 2(x + 60\%(x))$

$96 = 2(x + \frac{6}{100 } x)$

$96 = 2( \frac{100}{1 00} x + \frac{6}{100} x)$

$96 = 2( \frac{106}{100} x)$

$96 = \frac{106}{50} x$

$96 \div \frac{106}{50} = x$

$96 \times \frac{50}{106} = x$

$\frac{4800}{106} = x$