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aleksandr82 [10.1K]
3 years ago
8

How to find the area of a square whose perimeter is 7 meters​

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer:

A≈3.06

P Perimeter  

7

Using the formulas

A=a2

P=4a

Solving forA

A=1

16P2=1

16·72=3.0625

Anastasy [175]3 years ago
5 0

Answer:

Area=49

Step-by-step explanation:

Area of a square= L× L

perimeter=7

Area of a square=7×7

=49square

therefore, the area if a square whose perimeter is 7 is equal to 49square in meters

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Ms. Snyder is giving a 28-question test that is made up of multiple choice questions worth 2 points each and open response quest
zlopas [31]

Answer:

x *2 + (28-x)*4 = 100

Step-by-step explanation:

Given

Total number of questions in the paper = 28

Out of these 28 questions let us say that x number of questions are of 2 points and 28-x questions are of 4 points.

Also, the complete test is of 100 marks

Thus, the linear equation representing the

x *2 + (28-x)*4 = 100

8 0
3 years ago
Janelle has a 12 ounce can of soft drink. She drink 3/5 of the soft drink. How many ounces of soft drink are left in tbe can?
ivann1987 [24]

Answer:  4.8 ounces

Step-by-step explanation:

In total there are 12 ounces. If she drinks 3/5 of 12 you multiply 3/5 by 12.

3/5 * 12 would be equal to 3/5 * 12/1 which is 36/5. You have found how much she has drank. 36/5 is also equal to 7.2 ounces. Subtract 7.2 form 12 and you get 4.8 ounces.

Hope this helped!

7 0
3 years ago
1.3.12
kondaur [170]

Answer:

<h3><em>(12, -6)</em></h3>

Step-by-step explanation:

The formula for calculating the midpoint of two coordinates is expressed as shown;

M(X, Y) = [(x1+x2)/2,  (y1+y2)/2]

Given the midpoint of ST to be ((6, -2) and one endpoint T is (0,2), according to expression above;

X = (x1+x2)/2

Y = (y1+y2)/2

From the coordinates, X = 6, Y = -2, x1 = 0 and y1 = 2, to get x2 and y2;

X = (x1+x2)/2

6 =  (0+x2)/2

cross multiply

12 = 0+x2

x2 = 12-0

x2 = 12

For 2;

Y = (y1+y2)/2

-2 =  (2+y2)/2

cross multiply

-4 = 2+y2

y2 = -4-2

y2 = -6

<em>Hence the other endpoint S(x2, y2) is (12, -6)</em>

<em></em>

3 0
3 years ago
Which functions have real zeros at 1 and 4? Check all that apply.
Sophie [7]

Answer:

B, D

Step-by-step explanation:

These are the correct answers.

6 0
3 years ago
2(3x + 5) = 9x + 9 - 3x + 1​
ELEN [110]
2(3x+5)=9x+9-3x+1
(2)(3x)+(2)(5)=9x+9-3x+1
6x+10=9x+9-3x+1
6x+10=(9x-3x)+(9+1)
6x+10=6x+10
6x-6x+10=6x-6x+10
10=10
10-10=10-10
0=0
All real numbers are solutions.
3 0
3 years ago
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