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4 years ago

A spinner has 4 equal-sized sections. To win the game, the pointer must land on a purple section.

Mathematics

1 answer:

sveticcg [70]4 years ago

6 0

Answer:

You didn't include the statements so can you comment them below please.

1 favorable outcome / 4 outcomes in total = 0.25 = 25% to get wanted spot

0.25 purple = 1/4 = 25%

purple = 1/4

If you have any questions you can ask. Hope this helps

Step-by-step explanation:

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When 16x^3 - 12x^2 + 4x is divided by 4x the quotient is

klio [65]

$16x^3-12x^2+4x=4x(16x^2-3x+1)\\\\therefore\\\\(16x^3-12x^2+4x):4x=4x(4x^2-3x+1):4x=\boxed{4x^2-3x+1}$

6 0

3 years ago

2/3 of a number is equal to 20. What is the number?

frosja888 [35]

Let the number be x

ATQ
2/3 (x) = 20
x = 20 x 3/2
x = 30

the number = 30

4 0

3 years ago

Two particles, A and B, are initially 37.5 m apart. A is projected in a straight line directly towards B with initial speed 2 ms

Arisa [49]

Answer: 6.66 metres

Step-by-step explanation:

Given that the two particles, A and B, are initially 37.5 m apart.

Acceleration a = velocity/time

Make time t the subject of the formula.

Time t = velocity/acceleration

Time taken by particle A will be

Time t = 2/0.6 = 3.33 seconds

Let's use 2nd equation of motion

S = Ut + 1/2at^2

Distance covered by particle A will be achieved By substitute the values for speed and acceleration into the formula

S = 2 × 3.33 + 1/2 × 0.6 × 3.33^2

S = 6.66 + 0.3 × 11.1

S = 9.99 m

Time taken by particle B will be

Time t = 3/0.4 = 7.5 seconds

Distance covered by particle B will be by using the same formula

S = 3 × 7.5 + 1/2 × 0.4 × 7.5^2

S = 22.5 + 0.2 × 56.25

S = 33.75 metres

Adding the distance covered by particle A

Distance = speed × time

Distance = 2 × 3.33 = 6.66

the distance from A's starting point to C. Is 6.66 metres

6 0

3 years ago

The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length

Mademuasel [1]

Answer:

10.2 inches

Step-by-step explanation:

we know that

In this problem we have two cases

First case

The given lengths are two legs of the right triangle

$a=12\ in, b=15\ in$

Applying the Pythagoras Theorem

Find the length of the hypotenuse

$c^{2}=a^{2} +b^{2}$

substitute

$c^{2}=12^{2} +15^{2}$

$c^{2}=369$

$c=19.2\ in$

Second case

The given lengths are one leg and the hypotenuse

$a=12\ in, c=15\ in$

Applying the Pythagoras Theorem

Find the length of the other leg

$b^{2}=c^{2} - a^{2}$

substitute

$b^{2}=15^{2} - 12^{2}$

$b^{2}=81$

$b=9\ in$

Find the difference between the two possible lengths of the third side of the triangle

$19.2-9=10.2\ in$

3 0

4 years ago

Read 2 more answers

30.00

GalinKa [24]

Answer:

(13,-23)

Step-by-step explanation:

Comparing the image coordinates to the transformation rule, you see that ...

(x -4, y +15) = (9, -8)

Adding (4, -15) to these coordinates, we get ...

(x -4, y +15) +(4, -15) = (9, -8) +(4, -15)

(x-4+4, y+15-15) = (9+4, -8-15)

(x, y) = (13, -23) . . . . coordinates of D

4 0

3 years ago