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gizmo_the_mogwai [7]
3 years ago
14

a large container holds 8 gallons of water. it begins leaking at a constant rate. after 16 minutes, the container has 7 gallons

of water left. what’s the rate of water leaking?
Mathematics
1 answer:
Alona [7]3 years ago
5 0

Answer:

0.0625 gallons per minute (g/min)

Step-by-step explanation:

at the beginning, the container held 8 gallons of water. at the end, it has 7 gallons left. that means that the container lost 1 gallon altogether. it took 16 minutes to lose this amount, so you have to take 1 gallon divided by 16 minutes to get 0.0625 gallons of water lost per minute.

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5x+11=-3x+35 i need help solve for x
vaieri [72.5K]

Answer:

x = 3

Step-by-step explanation:

Let's solve your equation step-by-step.

5x + 11 = -3x +35

Add 3x to both sides.

5x + 11 + 3x = -3x + 35 + 3x

8x + 11 = 35

Subtract 11 from both sides.

8x + 11 - 11 = 35 - 11

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3 years ago
A company’s profit in dollars is modeled by the equation p(x) = –0.5x2 + 100x, where x represents the number of units sold.
serg [7]

Answers:

a. The company needs to sell 100 units to reach the maxmum profit.

b. The company's maximum profit is $5,000.

Solution:

a. How many unit does the company need to sell to reach the maximum profit?

p(x)=-0.5x^2+100x

This is a quadratic equation, and its graph is a parabola vertical (because the veriable "x" is square). Comparing with the general form:

p(x)=ax^2+bx+c; a=-0.5, b=100, c=0

a=-0.5<0 (negative), then the parabola opens downward, and it has a maximimun value (maximum profit) at its vertex.

We can find the abscissa of the vertex (units that the company needs to sell to reach the maximum profit using the following formula:

x=-b/(2a)

Replacing b by 100 and a by -0.5 in the formula above:

x=-100/[2(-0.5)]

x=-100/(-1)

x=100

The company needs to sell 100 units to reach the maximum profit.


b. What's the company's maximum profit?  

To determine the maximum profit we substitute the value of "x" obrained in part "a" in the quadratic equation:

x=100→p(100)=-0.5(100)^2+100(100)

p(100)=-0.5(10,000)+10,000

p(100)=-5,000+10,000

p(100)=5,000

The company's maximum profit is $5,000.

6 0
3 years ago
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