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Butoxors [25]
3 years ago
10

Two friends, Sasha and Maria, are growing out their hair. They plan to cut it off at a certain

Mathematics
1 answer:
34kurt3 years ago
8 0

Answer:

13 months, 49 cms

Explanation:

For Sasha, multiply 3 and 13 together for the growth per month. You should get 39, then add the 10 cm Sasha already has. The sum is 49.

For Maria, multiply 13 and 1 for the growth per month. You should get 13, then add the 36 Maria already has. The sum is also 49.

Hope this helps!

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A scale model of a rectangular building lot measures 7feet by 5 feet. If the actual house will be built using a scale factor of
Tamiku [17]
Actual area of the rectangular building = 5040 feet²
Step-by-step explanation:
Length of the rectangular building = 7 feet
Width of the rectangular building = 5 feet
Now, The building is made with a scale factor of 12
So, Actual length of the rectangular building = 84 feet
Actual width of the rectangular building = 60 feet
Now, Actual area of the rectangular building = Length × Width
⇒ Actual area of the rectangular building = 84 × 60
⇒ Actual area of the rectangular building = 5040 feet²
5 0
2 years ago
Which expression is equivalent to 7z + 7z?
Ierofanga [76]

Answer:

14z

Step-by-step explanation:

Since these are like-terms, they can be added together.

7z + 7z = 14z

6 0
2 years ago
A class contains 3 female and 9 male students. Find the probability that a student chosen at random is a male, and then a second
sammy [17]
9 +3 =  12 students

9 are male
 1st = 9/12 = 3/4
2nd = 8/11

3/4 * 8/11 = 6/11

 Answer = D) 6/11
8 0
3 years ago
E-1, e-2 and e-3 are three engineering students writing their assignments at night. Each of them starts at a different time and
Bas_tet [7]

E-3 will be the first student to start writing the assignment.

It is clearly stated in the statement that the order of starting the assignment and the order of the completion of the assignment is not the same, the digit in the name of the executive is also not same. This information puts some restrictions.

E-1 can neither be the first one to start nor the first one to complete. Similarly, E-2 cannot be the second one and E-3 cannot be the third one.

It is given that the last student (the third one) to start is the first student (the first one) to complete. This can neither be E-3 nor E-1. It is E-2

The final arrangement is as follows.

                                 Start           Complete

First                           E-3              E-2

Second                      E-1               E-3

Third                          E-2              E-1

E-3 is the first one to start writing the assignment.

More similar problems are solved in the link.

brainly.com/question/28391619?referrer=searchResults

#SPJ4

8 0
1 year ago
Giải các phương trình vi phân sau<br> y' - y/x+1 = 2
KatRina [158]

It looks like the differential equation is

y'-\dfrac y{x+1}=2

Multiply both sides by 1/(<em>x</em> + 1) :

\dfrac{y'}{x+1}-\dfrac y{(x+1)^2} = \dfrac2{x+1}

The left side is now a derivative of a product,

\left(\dfrac y{x+1}\right)' = \dfrac2{x+1}

Integrate both sides with respect to <em>x</em> :

\dfrac y{x+1} = 2\ln|x+1|+C

Solve for <em>y</em> :

y = 2(x+1)\ln|x+1| + C(x+1)

3 0
3 years ago
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