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frosja888 [35]
3 years ago
7

2) f(x) = 27x^6+ 1524x^3+125

Mathematics
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer:

Step-by-step explanation:

Let x^3 = y

f(x) = 27(x^3)^2 + 1524(x^3) + 125

f(x) = 27 y^2 + 1524y + 125

You can now put this into the quadratic formula. When you do, you get

(y + 0.0821)(y+56.3623) = 0

So now you substitute x^3 into this

(x^3 + 0.0821)(x^3 + 56.3623)

x^3 + 0.0821 = 0

x^3 = - 0.0821

cuberoot x^3 = cube root 0.0821

x = - 0.4346

x^3 = - 56.3623

x = - 3.8341

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Solve -3y(y-8)(2y+1)=0
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If a ball is thrown into the air with a velocity of 48 ft/s, its height in feet t seconds later is given by y = 48t − 16t2. Find
dimaraw [331]
The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
6 0
3 years ago
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