All categories

3 years ago

2) f(x) = 27x^6+ 1524x^3+125

Mathematics

1 answer:

Norma-Jean [14]3 years ago

8 0

Answer:

Step-by-step explanation:

Let x^3 = y

f(x) = 27(x^3)^2 + 1524(x^3) + 125

f(x) = 27 y^2 + 1524y + 125

You can now put this into the quadratic formula. When you do, you get

(y + 0.0821)(y+56.3623) = 0

So now you substitute x^3 into this

(x^3 + 0.0821)(x^3 + 56.3623)

x^3 + 0.0821 = 0

x^3 = - 0.0821

cuberoot x^3 = cube root 0.0821

x = - 0.4346

x^3 = - 56.3623

x = - 3.8341

You might be interested in

Help with Math PLZ (Questions in screenshot)

-Dominant- [34]

1.) Let's say that the circle on the graph below represents x. The arrow is pointing to all the numbers greater than x, which happens to be on -2. If it points right, this means that x can equal to any number greater than -2. So your answer is x > -2.

2.) For inequalities such as these, you can simplify just like what you do for normal equations. Let's isolate x.

$x - 7 > 10$

--> $x > 10 + 7$

---> $x > 17$

3.) $3x \leq 21$

--> $\frac{3x}{3} \leq \frac{21}{3}$

---> $x \leq 7$

4.) $5a - 2 < 18$

--> $5a < 18 + 2$

---> $5a < 20$

----> $\frac{5a}{5} < \frac{20}{5}$

-----> $a < 4$

5.) $2t + 8 \geq -4(t + 1)$

--> $2t + 8 \geq -4t - 4$

---> $2t + 4t \geq -8 - 4$

----> $6t \geq -12$

-----> $t \geq -2$

7 0

3 years ago

Convert 0.0000.489 to scientific notation

Volgvan

I do not understand why there are two decimal places.
But either ways if you are asking for :
0.0000489 then it is 4.89*10⁻⁵
0.489 then it is 4.89*10⁻¹
The trick is to count the zeroes to the first actual significant number you see and then write the number you counted with a negative sign for your power.
I hope this helps!

4 0

3 years ago

The model shows the addition expression 18 + 12.

Rashid [163]

Answer:

3(6+4) ._. hope this helps

3 0

4 years ago

$7 is what percent of 10$

marissa [1.9K]

Answer:

7/10

Step-by-step explanation:

you got 7 out of 10 dollars

5 0

3 years ago

Read 2 more answers

How do you simplify this expression step by step using trigonometric identities?

olga55 [171]

$\bf \textit{Pythagorean Identities}\\\\ 1+tan^2(\theta)=sec^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sec^2(\theta )cos^2(\theta )+tan^2(\theta )\implies \cfrac{1}{\begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }\cdot \begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} +tan^2(\theta ) \\\\\\ 1+tan^2(\theta )\implies sec^2(\theta )$

5 0

3 years ago