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leonid [27]
2 years ago
13

Which angle is the largest?​

Mathematics
1 answer:
igomit [66]2 years ago
5 0

Answer:

the 4th choice

Step-by-step explanation:

hope this helps

MAy I get braineist pls????????

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Which expressions are equivalent to 1/5 x 1/5 x 1/5 x 1/5<br><br><br><br> Choose 2 answers:
nordsb [41]

Answer:

You didn't say which two answers to choose from but they could possibly be 5^-4, (1/5)^4

Step-by-step explanation:

6 0
2 years ago
Given the following linear function sketch the graph of the function and find the domain and range f(x)=-3x+7
natka813 [3]
<h3>Answer:</h3>

see attached for a graph

domain and range: all real numbers

<h3>Step-by-step explanation:</h3>

The function is written in slope-intercept form, showing that it has a slope of -3 and a y-intercept of +7. The y-intercept (0, 7) is a point on the line, as is a point 1 unit to the right and down 3 units, (1, 4).

The graph will be the line through these two points.

_____

As with any odd-degree polynomial function, both domain and range are all real numbers: (-∞, ∞).

6 0
3 years ago
Quincy claims that if 80 coats are sold, the outside temperature is likely to be about 42°
nikklg [1K]

No. Quincy should have used the trend line to find the corresponding x value when y=80.


6 0
3 years ago
Read 2 more answers
I need Help!!!<br><br><br>(Question is attached)
katrin2010 [14]

Answer:

SEE BELOW

Step-by-step explanation:

1 - 12000 ft

2 - 10 minutes

3 - The third segment in he graph is not as steep as the first segment because the flight took more time to lose altitude than the time taken to gain altitude.

<em>Hope it helped</em>

3 0
2 years ago
In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

5 0
3 years ago
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