If it has no real solutions, that means the graph does not intersect the x axis
since we have ax^2+bx+c=0, the parabola opens either up or down
since the vertex is in the second quadrant (x is negative and y is positive in this reigon) and the graph does not cross the x axis, the parabola must open up
if the value of 'a' is positive, then the parabola opens up
so 'a' must be positive
if it is translated to the 4th quadrant, then the vertex is now below the x axis
it will now have 2 x intercepts because the vertex is in the 4th quadrant and look at a graph of a parabola opening up with vertex in 4th quadrant and seehow many time it crosses the x axis
i had to do the answer as a pic cuz my iPad is gonna die.
sorry <:)
Answer:
D
Step-by-step explanation:
D because it is always true
10t = b - 4
12b+8t = $348
This is a system of equations. I’ll be solving through substitution.
In the first equation. solving for b (the easier variable to isolate) gives you:
b = 10t + 4
Substitute this into the second equation:
12(10t+4) +8t = 348
120t+48+8t = 348
128t = 300
t = 2.34375 —> round it to the nearest cent to get 2.34 dollars
b = 10t+4
b = 10(2.34)+4
b = 27.4 dollars
Answer:
2300
Step-by-step explanation:
We are given that
Out of 200 , four ducks are tagged.
We have to find the number of ducks in the preserve if 46 ducks are tagged.
Let x be the number of ducks in the preserve.
If number of tagged ducks increases then number of preserved ducks also increases.It is in direct proportion.
According to question
x=2300
