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1 year ago

PLEAASE HELP I NEED UNGROUNDED

Mathematics

2 answers:

olga2289 [7]1 year ago

7 0

Answer: 3x - 2

Step-by-step explanation:

In this question, we have to find two unknown variables: a and b. To know a, we have to calculate the distance from two coordinates who are intercepted by the function in which the variable we’re looking for is. In this case, we have (1,1) and (0,-2). We first take the biggest coordinate from both and subtract the other one from it. So we have 1 - - 2 = 3. To know the second variable, b, we have to look on the graph where the “y” lands on when “x” = 0. In this case, we have -2. The equation is 3x - 2.

omeli [17]1 year ago

4 0

Answer:

y=3x-2

Step-by-step explanation:

The formula for slope is y=mx=b

You can find the slope by finding two points that lie on the line (1,1) & (0,-2)

The formula for slope is $m=\frac{y_{2} -y_{1}}{ x_{2} -x_{1} }$

You plug the values in and you get $m=\frac{1-(-2)}{ 1 -0 }$

Simplify and you get 3

The slope is 3

The y-intercept (b) is -2

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3 years ago

Evaluate the surface integral:S

rjkz [21]

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where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

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$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
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So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
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3 years ago

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Fantom [35]

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