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3 years ago

Solve the following quadratic equation for all values of xx in simplest form. 4(x-2)^2=16

Mathematics

1 answer:

kvv77 [185]3 years ago

8 0

Answer:

$x=4, x=0$

Step-by-step explanation:

I answered this here, lol.

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Fayzansabeel is a very brainly user!!!

wariber [46]

Answer:

oh ok.. can i get ur intro??

3 0

2 years ago

Read 2 more answers

Find the maximum value of the function for the polygonal convex set determined by the given system of inequalities.

V125BC [204]

Answer:

A. at (8,7) the maximum value is 98

Step-by-step explanation:

First draw the region, that is bounded by all

inequalities. This is the triangle with vertices

(6,1), (2,5) and (8,7).

Now you can see where the line f(x,y)=7x+6y

intersect this region. The maximum value will be

at endpoints of this region:

• at (6,1), f(6,1)=7-6+6-1=42+6=48;

at (2,5), f(2,5)=7·2+6.5=14+30=44;

• at (8,7), f(8,7)=7.8+6-7=56+42=98.

Thus, the maximum value of the function is 98 at

the point (8,7).

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8 0

2 years ago

3. Which relation is a function?

Pani-rosa [81]

Answer:

Step-by-step explanation:

Recall that functions are defined only if for each value in the domain produces one and only one value in the range.

If we view the relations in the questions as x-y coordinates, this means that for every x-value, you can only have one y-value

Lets evaluate the options:

A) we can see that for x = -3, this gives 2 possible values for y i.e (-3,4) and (-3,8) (hence this is not a function)

C) we can see that for x = 3, this gives 2 possible values for y i.e (3,-8) and (3,8) (hence this is not a function)

D) we can see that for x = -3, this gives 2 possible values for y i.e (-3,4) and (-3,8) (hence this is not a function)

the only choice where this doesn't occur is choice B

6 0

4 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

3 years ago

Can you try to solve this plz

Nostrana [21]

Answer:

50 dgrees

Step-by-step explanation:

staruight line is 180 so 180 minus 130 is 50

8 0

3 years ago