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2 years ago

11

Considering the sign up fee and monthly membership fee for a gym the equation c=30m+25 can be used to represent the total cost o

f a gym membership for m months what is the amount of the sign up fee

1 answer:

Naddik [55]2 years ago

7 0

Answer:

$25

Step-by-step explanation:

Cost = 30 x months + 25

Every month you will pay 30$

At 0 months when you sign up substitute m=0

Cost = 30x 0 +25 = 0 +25 =25

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Help me plz i don't understande

Misha Larkins [42]

Multiply 8 by 4 and that will give you 32 then add 9 and you get 41 so the answer is 41 years old

6 0

2 years ago

Read 2 more answers

1/3 divided by 2 divided

KatRina [158]

Answer:

1/6

Step-by-step explanation:

1/3 diveded by 2/1

1/3x1/2 = 1/6

Hope it helps:)

6 0

2 years ago

What is the answer to m

tigry1 [53]

Answer:

Height of a cell tower is, 30 m

Step-by-step explanation:

Proportion states that the two fractions or ratios are equal.

As per the given statement:

Let height of a cell tower be h.

Height of a pole = 3m ,

Shadow of a pole = 4 m and

shadow of a cell tower = 36+4 = 40 m

By definition of proportion;

$\frac{\text{Height of a cell tower}}{\text{Shadow of a cell tower}} = \frac{\text{Height of a pole}}{\text{Shadow of a pole}}$

Substitute the given values we get;

$\frac{h}{40}=\frac{3}{4}$

by cross multiply we get;

$4h = 120$

Divide both sides by 4 we get;

h = 30 m

Therefore, the height of a cell tower is, 30 m

5 0

2 years ago

Is the equation y = x3 even, odd, or neither?

ohaa [14]

Let be y =f(x)= x3, f(-x) = (-x)^3 = - x^3 = - f(-x), f(-x) = (-x)^3, f(-x) = - f(<span>-x)
the equation is odd</span>

5 0

2 years ago

www.g The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulb

damaskus [11]

Answer:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

Step-by-step explanation:

For this problem we have the following parameters given:

$\mu = 40, \sigma =8$

And for this case we want to find the percentage of lightbulb replacement requests numbering between 24 and 40.

From the empirical rule we know that we have 68% of the values within one deviation from the mean, 95% of the values within 2 deviations and 99.7% within 3 deviations.

We can find the number of deviations from themean for the limits with the z score formula we got:

$z=\frac{X-\mu}{\sigma}$

And replacing we got:

$z=\frac{24-40}{8}=-2$

$z=\frac{40-40}{8}=0$

And then the percentage between 24 and 40 would be $\frac{95}{2}= 47.5 \%$

5 0

3 years ago