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3 years ago

Find the range of possible values of n.

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

6 0

Answer:

B. 6 < n < 25

Step-by-step explanation:

We are given the triangles WXY and WZY with sides XY and ZY congruent and equal to 8.

As the sides WX = 11 > WZ = 9.

Then, the angles opposite to WX will be greater than the angle opposite to WZ.

i.e. ∠WYX > ∠WYZ

i.e. (7n+5)° > 47°

i.e. 7n° > 42°

i.e. n > $\frac{42}{7}$ °

i.e. n > 6°

Since in ΔWXY, the sum of all three angles is 180°.

This means that (7n+5)° < 180°

i.e. 7n < 175°

i.e. n < $\frac{175}{7}$ °

i.e. n < 25°

Hence, we get that the range of n is 6 < n < 25.

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Find cot theta if csc theta = sqrt17/4 and tan theta >0.

Lorico [155]

Answer:

$tan \theta = 4$

Step-by-step explanation:

We know that

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Given :

$cosec \theta =\frac{\sqrt{17}}{4}\\$

So 4 is the opposite side of theta.

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We use the Pythagorean theorem to find for the adjacent side.

$a = \sqrt{17 - 4^2} = \sqrt{17-16} = 1$

$Therefore, \ tan \theta = \frac{4}{1} = 4$

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3 years ago

F(x)=2x 2 −x+9 \text{Find }f(4) Find f(4)

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Answer:

Step-by-step explanation:

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3 years ago

Will the Brainliest answer!!! solve for x and y. 946x+642y=911

Ronch [10]

While you cannot solve 946x+642y=911 for numerical values of x and y, you can indeed solve 946x+642y=911 first for x and then for y:

-911 - 642y

For x: 946x+642y=911 becomes 946x = 911 - 642y, or x = ------------------

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911-946x

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4 years ago

Read 2 more answers

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

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4 years ago

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myrzilka [38]

Answer:

Step-by-step explanation:

4x-3+7x+1

4x, 7x are like terms because the both have an x

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3 years ago