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alexira [117]
2 years ago
6

Which equation is graphed on the number line at right ?

Mathematics
1 answer:
Yuki888 [10]2 years ago
5 0

Answer:

D.)|x| + 3 < 6

Step-by-step explanation:

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Gnoma [55]

maybe 108 is the answer.

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2 years ago
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Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-2, 2)A(−2,2
taurus [48]

Answer:

Step-by-step explanation:

The rectangle ABCD has vertices A(-2,2), B(6,2), C(6,3) and D(-2,3).

Now, length of side AB = [6 - (- 2)] = 8 units.

{Since the line AB is parallel to the x-axis, so the length of the segment AB will be the difference between the x-coordinates of the points A and B}

Again, line BC is parallel to y-axis and hence the length BC = (3 - 2) = 1 units.

Therefore, the area of the rectangle ABCD will be (8 × 1) = 8 sq. units. (Answer)

7 0
2 years ago
What is the leading coefficient of the polynomial when written in standard<br> form?<br> 872 +9+ 5x
lianna [129]

Answer:

5

Step-by-step explanation:

The coefficient is known as "the number in front of the letter,' so since 5 is in front of the x, 5 would be the leading coefficient, especially since the outcome would be 5x+881.

3 0
3 years ago
ASAPPP!!!! HELP I WILL GIVE 100POINTS AND BRAINLIST Question 9 (Essay Worth 10 points)
Luda [366]

Answer:

Part A)

The <em>x-</em>intercepts are (-1/4, 0) and (4, 0).

Part B)

The vertex is a maximum because the leading coefficient is negative.

The vertex is (1.875, 72.25).

Part C)

We can plot the zeros and the vertex, and connect them with a curve.

Step-by-step explanation:

The function given is:

f(x)=-16x^2+60x+16

Part A)

To find the <em>x-</em>intercepts of the function, set the function equal to 0 and solve for <em>x: </em>

<em />0=-16x^2+60x+16<em />

We can divide both sides by negative four:

0=4x^2-15x-4

Factor:

0=(4x+1)(x-4)

Zero Product Property:

x-4=0\text{ or } 4x+1=0

Solve for each case:

\displaystyle x=-\frac{1}{4}\text{ or }x=4

Hence, our zeros are:

\displaystyle \left(-\frac{1}{4}, 0\right)\text{ and } \left(4, 0\right)

Part B)

Note that the leading coefficient of our function is negative.

So, our function will be concave down.

Hence, our vertex will be the maximum.

The vertex is given by:

\displaystyle \left(-\frac{b}{2a}, f\left(-\frac{b}{2a}\right)\right)

In this case, <em>a </em>= -16, <em>b</em> = 60, and <em>c</em> = 16.

Find the <em>x-</em>coordinate of the vertex:

\displaystyle x=-\frac{(60)}{2(-16)}=\frac{15}{8}=1.875

Substitute this back into the function to find the <em>y-</em>coordinate:

f(1.875)=-16(1.875)^2+60(1.875)+16=72.25

Hence, our vertex is:

(1.875, 72.25)

Part C)

Since we already determined the zeros and the vertex, we can plot the two zeros and the vertex and draw a curve between the three points.

The graph is shown below. Again, to do this by hand, simply plot the three points and connect them with a parabola. If necessary, we can also find the <em>y-</em>intercept.

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L. Extend Your Thinking Dave is packin
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Dave can put 5 of each fruit into each box without exceeding 5 kilograms.
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