Answer:
(a) Equation: 
(b) 7.5 gallons
Step-by-step explanation:
Given
Current Gas = 10 gallon
Every Hour = -1.25 gallon
Solving for (a): An equation for the scenario
This question represents an Arithmetic Progression and will be solved using the following formula:

Where


Substitute these values in the formula


Collect Like Terms


Solving for (b): In this case, n - 3
Substitute 3 for n in 



<em>7.5 gallon of gas left</em>
Step-by-step explanation:
- 4x+5= 20
- 4x=20-5
- 4x= 15
- x= 15/4
therefore the answer is option
b) X= 15/4
<h2>mark me as brilliest and follow me first.....</h2>
The answer is c. 1/9.
If x = -2, y = -1, z = 3
then, (-2(-1) -(-1)^2) / 3(3)
(2 - 1)/3(3)
1/9
Answer:
Can you please look at your question and tell me the whole thing. pls and ty :)
Step-by-step explanation:
Answer:
See Below.
Step-by-step explanation:
We want to show that the function:

Increases for all values of <em>x</em>.
A function is increasing whenever its derivative is positive.
So, find the derivative of our function:
![\displaystyle f'(x) = \frac{d}{dx}\left[e^x - e^{-x}\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5Be%5Ex%20-%20e%5E%7B-x%7D%5Cright%5D)
Differentiate:

Simplify:

Since eˣ is always greater than zero and e⁻ˣ is also always greater than zero, f'(x) is always positive. Hence, the original function increases for all values of <em>x.</em>