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3 years ago

Someone help quick!?

Mathematics

1 answer:

natulia [17]3 years ago

6 0

Answer:

can you write the question so I can understand what to do

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Which of the following best describes the intersection of two planes? (Points : 5)

charle [14.2K]

<span>In geometry, planes are two-dimensional spaces which extend infinitely. If they do not intersect at all, they are considered parallel. However, if they do intersect, that intersection come in the form of an infinitely-extending collection of 1-dimensional points, which collectively form a line. As such, the answer is "line".</span>

4 0

3 years ago

Joe worked 12 hours and packed 32 cartons. Bob worked 25 hours and packed 64 cartons. Did Joe and Bobwork at the same rate?O YES

Bas_tet [7]

To be able to compare the rates, we will write them in fraction form.

The fraction that represents Joe's rate is:

$\frac{32}{12},$

and the fraction that represents Bob's rate is:

$\frac{64}{25}\text{.}$

Simplifying the above fractions, we get:

$\begin{gathered} \frac{32}{12}=\frac{8}{3}, \\ \frac{64}{25}=\frac{64}{25}\text{.} \end{gathered}$

Since:

$\frac{8}{3}\ne\frac{64}{25}$

then Bob and Joe did not work at the same rate.

Answer:

No, Bob and Joe did not work at the same rate.

4 0

1 year ago

Aaron makes $45 dollars per day delivering newspapers. He earns 0.75 for each newspaper he delivers. How many newspaper, n, must

ANEK [815]

Answer:

20 newspapers

Step-by-step explanation:

First create an equation.

y = 0.75x + 45

Now substitute 60 y and solve for x.

60 = 0.75x + 45

60 - 45 = 0.75x + 45 - 45

15/0.75 = 0.75x/0.75

x = 20 newspapers

5 0

2 years ago

Read 2 more answers

A student bought tickets online the total cost c in dollar of t, tickets can be found using the fuction below c=24.50t+9.50

dalvyx [7]

What is the total cost or it is unsolvable?

8 0

4 years ago

use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 ), (15 comma

lyudmila [28]

Answer:

volume V of the solid

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.

Each slice is a quarter of cylinder 5/n thick and has a radius of

-k(5/n) + 5 for each k = 1,2,..., n (see picture)

So the volume of each slice is

$\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}$

for k=1,2,..., n

We then add up the volumes of all these slices

$\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}$

Notice that the last term of the sum vanishes. After making up the expression a little, we get

$\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2$

But

$\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)$

we also know that

$\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}$

and

$\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}$

so we have, after replacing and simplifying, the sum of the slices equals

$\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}$

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

$\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}$

and the volume V of our solid is

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

3 0

3 years ago