The Equation in terms of m, m^2+7m+10=0
What is substituting in the equation ?
substituting means changing or replacing the values in the given equation.
Calculation:
Given equation is (x^2+3)^2+7x^2+21=-10
and m= X^2 + 3.
make the given equation in the form X^2 + 3,
now,
(x^2+3)^2+7x^2+21=-10
(x^2+3)^2+7(x^2+3)=-10
where,
X^2 + 3= m
after putting the value or replacing the values
we get, m^2+7m=-10
m^2+7m+10=0
the above equation is in the form of "m".
The Equation in terms of m, m^2+7m+10=0
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Answer: 11 weeks
Step-by-step explanation: 11 x 10 + 10 = $120 and 11 x 6 +54 = $120
Step-by-step explanation:
V = h × w × l
7650 = 9 × 25 × l
So,
l = 7650 ÷ 9 ÷ 25
l = 850 ÷ 25
l = 34
For the final, the length is 34.
Answer: 0.935
Explanation:
Let S = z-score that has a probability of 0.175 to the right.
In terms of normal distribution, the expression "probability to the right" means the probability of having a z-score of more than a particular z-score, which is Z in our definition of variable Z. In terms of equation:
P(z ≥ S) = 0.175 (1)
Equation (1) is solvable using a normal distribution calculator (like the online calculator in this link: http://stattrek.com/online-calculator/normal.aspx). However, the calculator of this type most likely provides the value of P(z ≤ Z), the probability to the left of S.
Nevertheless, we can use the following equation:
P(z ≤ S) + P(z ≥ S) = 1
⇔ P(z ≤ S) = 1 - P(z ≥ S) (2)
Now using equations (1) and (2):
P(z ≤ S) = 1 - P(z ≥ S)
P(z ≤ S) = 1 - 0.175
P(z ≤ S) = 0.825
Using a normal distribution calculator (like in this link: http://stattrek.com/online-calculator/normal.aspx),
P(z ≤ S) = 0.825
⇔ S = 0.935
Hence, the z-score of 0.935 has a probability 0.175 to the right.
Do you have any more information there really is no other way to solve it with out more information
