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mario62 [17]
3 years ago
5

Shape of quadrilateral with 4 unequal sides

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0
I wanna say......Trapezoid? 
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The line would intersect with the y-axis at (0,0)
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9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
2 years ago
Shown below is the solution to the linear program for finding Player A's optimal mixed strategy in a two-person, zero-sum game.
Luba_88 [7]

Answer:

Following are the answer to this question:

Step-by-step explanation:

For Option a:

Its optimal mixed approach for Player A's to Player A  

A1 with a chance of .05 utilizing technique  

Using the .60 chance strategy for A2  

Use the .35 possibility strategy for A3  

For Option b:

Optimal level mixed approach for team B:  

Use the strategy for B1 with a probability of 50  

Using the chance strategy for B2 at .50  

no  use strategy for B3  

For Option c:

The estimated gain of Player A will be= 3.500

For Option d:

The estimated loss of Player B will be 3.500

8 0
3 years ago
Choose whether the probability is mutually exclusive or not
Semmy [17]

9514 1404 393

Answer:

  mutually exclusive

Step-by-step explanation:

The formula of interest is ...

  P(A or B) = P(A) + P(B) - P(A and B)

Filling in the given values, we have ...

  9/10 = 2/5 + 1/2 - P(A and B)

Solving for P(A and B), we get ...

  P(A and B) = 2/5 +1/2 -9/10 = 4/10 +5/10 -9/10

  P(A and B) = 0

__

Events are mutually exclusive when <em>they can never happen at the same time</em>. That is, P(A and B) = 0.

The events A and B are mutually exclusive.

4 0
2 years ago
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