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3 years ago

What is the greatest common factor of 12, 40, and 28

Mathematics

1 answer:

cupoosta [38]3 years ago

6 0

Answer:

Step-by-step explanation:

4*3=12

4*10=40

4*7=28

There is no higher number that goes into all three.

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PLS HELP TEST ILL GIVE BRAINLIEST

dybincka [34]

Answer:

X must be negative

because the answer is x=-8

Step-by-step explanation:

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2 years ago

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Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting t

maria [59]

Using the Pythagorean on the right triangle PQR, with PQ and QR as the legs and PR as the hypotenuse,

$14^2 +6^2 =(PR)^2\\\\(PR)=\sqrt{14^2 +6^2}\\\\PR \approx \boxed{15.23 \text{ ft}}$

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1 year ago

Logan is 2 years older than Lindsey .Five years ago, the sum of their age was 30 . Find Lindsey's current age

marusya05 [52]

X is 2 more than y
x=2+y

5 years ago (x-5 and y-5)
sum is 30
x-5+y-5=30
x+y-10=30

x=2+y
sub 2+y for x
2+y+y-10=30
2y-8=30
add 8 to both sides
2y=38
divide both sides by 2
y=19

Lindsey is 19

4 0

2 years ago

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Ashlyn and Meg went to the mall. Ashlyn spent $120.01. If they spent $252.85 together, how much did Meg spend?

german

252.85 - 120.01 = 132.84
Meg would have spent $132.84.

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2 years ago

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(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$