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Lelechka [254]
3 years ago
11

What is the greatest common factor of 12, 40, and 28

Mathematics
1 answer:
cupoosta [38]3 years ago
6 0

Answer:

4

Step-by-step explanation:

4*3=12

4*10=40

4*7=28

There is no higher number that goes into all three.

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Lol this one is kind of confusing but i think it’s C because there can be a centipede that is missing a leg lol
7 0
3 years ago
Read 2 more answers
Use the function below to find f(4).
Afina-wow [57]

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

Simply replace X with 4

5 0
3 years ago
The length of a phone conversation is normally distributed with a mean of 4 minutes and a standard deviation of .6 minutes. What
Ivanshal [37]

Answer:

0.04746

Step-by-step explanation:

To answer this one needs to find the area under the standard normal curve to the left of 5 minutes when the mean is 4 minutes and the std. dev. is 0.6 minutes.  Either use a table of z-scores or a calculator with probability distribution functions.

In this case I will use my old Texas Instruments TI-83 calculator.  I select the normalcdf( function and type in the following arguments:  :

normalcdf(-100, 5, 4, 0.6).  The result is 0.952.  This is the area under the curve to the left of x = 5.  But we are interested in finding the probability that a conversation lasts longer than 5 minutes.  To find this, subtract 0.952 from 1.000:   0.048.  This is the area under the curve to the RIGHT of x = 5.

This 0.048 is closest to the first answer choice:  0.04746.

8 0
3 years ago
Prove: Every point of S=(0, 1) is an interior point of S.
myrzilka [38]

Answer:

Proved

Step-by-step explanation:

To prove that every point in the open interval (0,1) is an interior point of S

This we can prove by contradiction method.

Let, if possible c be a point in the interval which is not an interior point.

Then c has a neighbourhood which contains atleast one point not in (0,1)

Let d be the point which is in neighbourhood of c but not in S(0,1)

Then the points between c and d would be either in (0,1) or not in (0,1)

If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.

Then we find that dn is a boundary point of S

But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.

Every point of S=(0, 1) is an interior point of S.

3 0
3 years ago
What is the value of this expression when a=20
Aloiza [94]

Answer:

20

Step-by-step explanation:

A=20

4 0
2 years ago
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