Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
= (cos^2x/sin^2x) { sin^2x }
= cos^2x
Answer:
Yes, ASA
Step-by-step explanation:
It is angle- side- angle because of the HLK< it is ASSA but since the SS are the same, its ASA.
Hope this helps!
Answer:
Angle y and Angle x are complementary angles
Step-by-step explanation:
we know that
If
sin(y°)=cos(x°)
then
Angle y and Angle x are complementary angles
so
∠y+∠x=90°
∠x=90°-∠y
sin(y°)=cos(90°-y°)
therefore
The sine of an angle is equal to the cosine of its complementary angle
Answer:
70
Step-by-step explanation:
