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3 years ago

Which fraction is equivalent to 2/6?

Mathematics

2 answers:

natima [27]3 years ago

6 0

Answer:

1/3, 2/6, 3/9, 4/12

Step-by-step explanation:

almond37 [142]3 years ago

4 0

Answer:

Step-by-step explanation:

if you simlpify 2/6 you would get one third times that by three its 3 ninths

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How do you subtract integers

IgorC [24]

Answer:

hzghdooejrjsjhsjajlaoskryrj

7 0

3 years ago

Read 2 more answers

There are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom. The three candidates that rece

sveticcg [70]

Answer:

Step-by-step explanation:

Given that there are 8 candidates for student government: Hal, Mary, Ann, Frank, Beth, John, Emily, and Tom.

The three candidates that receive the highest number of votes become candidates for a runoff election.

i.e. 3 persons out of 8 to be selected for becoming candidates for a runoff election.

Since order does not matter we use combinations here

3 persons out of 8 can be done in 8C3 ways

= 56

no of 3-candidate combinations possible are 56

3 0

4 years ago

How can I solve this: |n| ≥ n

valina [46]

$|n| \geq n$

For $n\leq 0$

$|n| \geq n \Leftrightarrow -n\geq n \Rightarrow 2n\leq0 \Rightarrow n\leq0$

For $n>0$

$|n| \geq n \Leftrightarrow n\geq n \Rightarrow 0\geq0\Rightarrow x\in\mathbb{R}$

$x>0 \vee x\leq 0 \Rightarrow \boxed{x\in\mathbb{R}}$

-------------------------------------------------------------

$|n| \leq n$

For $n\leq0$

$|n|\leq n\Leftrightarrow -n\leq n \Rightarrow 2n\geq 0 \Rightarrow n\geq 0\\
n\geq 0 \wedge n\leq 0 \Rightarrow n=0$

For $n>0$

$|n|\leq n \Leftrightarrow n\leq n \Rightarrow 0 \leq 0\Rightarrow n\in \mathbb{R}\\
n\in \mathbb{R} \wedge n>0 \Rightarrow n>0$

$n>0 \vee n=0 \Rightarrow \boxed{x\geq0}$

5 0

4 years ago

A student was asked to find a 90% confidence interval for the proportion of students who take notes using data from a random sam

Scorpion4ik [409]

Answer:

After use the formula we got the following result for the 90% confidence interval (0.13 <p<0.34)

And the conclusion for this case would be:

e. With 90% confidence, the proportion of all students who take notes is between 0.13 and 0.34.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of students who take notes

$\hat p$ represent the estimated proportion of students who take notes

n is the sample size required

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.