Hello,
Let's be a the greatest number, b the smallest
Method 1:
a+b=37 ==>b=37-a
a*b=36==>a(37-a)=36
==> a²-37a+36=0
==>a²-36a-a+36=0
==>a(a-36)-(a-36)=0
==>(a-36)(a-1)=0
(a=36 and b=37-36=1) or (a=1 and b=37-1=36) but a>b ==>exclude
==>a-b=35
Method 2:
a*b=36
a+b=37 ==>(a+b)²=37²
(a+b)²-4ab=37²-4*36
==>a²+2ab+b²-4ab=1225
==>(a-b)²=35²
==>a-b=35 or a-b=-35 (to exclude since a>b)
First, lets break up the equation into pieces.
The first variable is slope, in your case here, we have a slope of -3 or -3/1.
The other variable is the y-intercept, which is where place on the graph where you plot (0,X), in your case here we got (0,-4). That is the y-intercept.
to graph it you have to plot the y-intercept, and then identify the slope.
Here is an example.
X= 16.
All you have to do is isolate x to one side.
To do this, subtract 10 from 26.
26-10=16
Answer:
C. heteroscedasticity
Step-by-step explanation:
The OLS regression assumption of error variance being constant irrespective of independent variables, is called Homoscedasticity.
Var (u | x) = σ^2 (u) ;
where u = error term, x = independent variable, σ^2 (u) = constant error variance
The violance of this assumption ie Var (u | x) is related to independent variable x, is called Heteroscedasticity.