Explanation:
These base pair relationships are often called Chargaff's rules of DNA base pairing, named after the Columbia University scientists who observed that there are equal molar concentration of A & T, as well as G & C in most DNA molecules.
If an individual has an <u>increased</u> rate of blood flow to the skin,such as would happen with emotion or alcohol consumption ,their skin takes on a <u>reddish</u> tinge.
Explanation:
Our skin is provided with a large number of blood capillaries. These capillaries bring blood and nutrients to the layers of skin. Whenever vasodilation of these capillaries occur, the blood flow to the skin increases and the skin gets a reddish tinge.
During an emotional upsurge such as embarrassment causes the adrenal glands to release adrenaline.
Adrenaline as well as alcohol vasodilates the blood vessels and increases the flow of blood to the skin. Hence, the skin gets a reddish tinge.
Answer:
<h2>a rift valley is forming</h2>
Explanation:
Answer:
Following Statements are true.
1. Cells receive molecular signals that communicate their position in relation to other cells.
3. Differential gene expression affects the developmental process in animals.
4. Positional information controls pattern formation.
6. Homeotic genes code for transcription factors that control the development of segment-specific body parts.
Explanation:
The formation of an eukaryotic organisms's spatial organization which includes organ formation and tissue arrangement is called as Pattern formation.
Molecular signals are received by cell. This phenomenon collectively refereed as positional information. Through this phenomenon cells are informed about their locomotion with respect to body axes and other cells. Regulation of pattern formation is controlled by Positional information.
When body axes is established a gene called homeotic gene start working as regulatory genes. This gene identify specific body segment in an organism which results in the formation of segment-specific body structures in the correct locations on the body.
Answer:
A. 
B. 
C. 
D. 
Explanation:
Hello.
In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:
Thus, we proceed as follows:
A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.
B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.
C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.
D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.
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