F(x)=-x+12/4 Not sure if this is right..
What you do is get into the form
(x-h)^2+(y-k)^2=r^2
(h,k) is center
r=radis
complete the square with x and y
x^2+y^2-2x+4y-11=0
group x and y terms together
(x^2-2x)+(y^2+4y)-11=0
take 1/2 of linear coefieicnt and add postive and negative
for x^2-2x, -2/2=-1, (-1)^2=1
for y^2+4y, 4/2=2, 2^2=4
(x^2-2x+1-1)+(y^2+4y+4-4)-11=0
complete the square
(x-1)^2-1+(y+2)^2-4-11=0
add like terms
(x-1)^2+(y+2)^2-16=0
add 16 both side
(x-1)^2+(y+2)^2=16
(x-(1))^2+(y-(-2))^2=4^2
(x-h)^2+(y-k)^2=r^2
(h,k)
(1,-2)
r=4
center is (1,-2)
radius is 4 units
9514 1404 393
Answer:
D. 3, 4, 5, 6
Step-by-step explanation:
3x + 2 > 8 . . . . . . given
3x > 6 . . . . . . . . . subtract 2 from both sides
x > 2 . . . . . . . . . . divide both sides by 2
Any set of values that includes 2 or any smaller numbers is NOT a solution set. The only set with numbers greater than 2 is ...
D. 3, 4, 5, 6
Answer:
x=14
y=10
Step-by-step explanation:
The median divide the data‘s set into two parts with the same frequency = 50%
then we must have 2+5+x+12+17 = 50 ⇔ 36+x=50 then x =50-36=14
also 20+y+9+7+4=50 ⇔ y=10
