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mestny [16]
3 years ago
13

Which of the following is not a way of generating random numbers? A. random number tables B. using phone numbers selected at ran

dom in a local phone book C. using the internet D. books of random numbers
Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

well all of these look like a way so we have to use elimination method

A : random number tables : well it has random numbers so X out

B: PHONE NUMBERS: well phone numbers are random so X out

C: USing the internet : totally X out

D: books of random numbers: X out

so none of the above i guess

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A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv
mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

p=\frac{1}{6}

Now, probability of failure is given by the formula:

q=1-p=1-\frac{1}{6}=\frac{5}{6}

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

P(x) = ^nC_xp^xq^{n-x}

Plug in all the given values and find the probability of 14 successes. This gives,

P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087

Therefore, the experimental probability of throwing a five is 0.087.

8 0
3 years ago
Help plz I really need the help​
Colt1911 [192]

Answer:

the answer might be either one of the four

3 0
3 years ago
9. Triangle Construction pays Square Insurance $5,980
xxTIMURxx [149]

The triangle pay $32 more for that day than it paid per day during the first period of time.

Step-by-step explanation:

The given is,

              Triangle Construction pays Square Insurance $5,980

               To insure a construction site for 92 days

               To extend the  insurance beyond the 92 days costs $97 per day

               Triangle extends the insurance by 1 day

Step:1

              Insurance per day from the 92 days period,

                                                                           = \frac{Total insuratio for 92 days}{Period}

               Where, Total insurance for 92 days = $ 5,980

                                                               Period = 92 days

               From the values, equation becomes,

                                                                            =\frac{5980}{92}

                                                                           = $ 65 per day

Step:2

              Insurance per day after the 92 days,

                                                                           = $ 97

               Amount Pay for that day than it paid per day during the first period of time,

                                                                            =(97-65)

                                                                           = $32

Result:

             The triangle pay $32 more for that day than it paid per day during the first period of time, if  the Triangle Construction pays Square Insurance $5,980 to insure a construction site for 92 days and to extend the  insurance beyond the 92 days costs $97 per day.

                                                                         

8 0
3 years ago
Tony has a bucket filled with green, blue, yellow, and red markers. He removes 3 markers from the bucket, with replacement. Sele
Margaret [11]

Answer:

Options A), B), C), D)

Step-by-step explanation:

There are 4 colors of markers.

Take out three "with replacement" markers.

As there is replacement, then the number of markers in the cube does not change in each trial.

A) There is a chance that when you get the three markers always get the same color.

B) It is likely to get a marker of each color

C) If 3 markers are taken it is likely to get the same amount of green and blue markers. For example, if there are 3 markers obtainable: blue, green, yellow. Then the number of blues and yellows is the same.

D) If 3 markers are taken it is likely to obtain the same amount of red and yellow markers. For example, if there are 3 markers you could obtain: red, yellow, blue. Then the number of reds and yellows is the same.

E) <u><em>It is impossible for this to happen</em></u>, because if only 3 markers of two different colors are taken, then there will always be 2 markers of one color and only one marker of another color:

green, green, yellow

blue, blue, green

blue, red, red .....

So the first 4 results are possible. Only the last result is impossible to obtain

5 0
3 years ago
GUYS PLS HELP MEEEE I REALLY NEED HELP
PilotLPTM [1.2K]

Answer:

x = 22.45

Step-by-step explanation:

Have a good day :)

6 0
3 years ago
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