The probability that a randomly selected carton has a puncture or a smashed corner is 12.6%.
In this problem, the events are:
Event A: Puncture.
Event B: Smashed corner.
The "or" probability is given by:
∩
5% have a puncture, hence 
8% have a smashed corner, hence 
0.4% have both a puncture and a smashed corner, hence
Then:

Therefore, The probability that a randomly selected carton has a puncture or a smashed corner is 12.6%.
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Answer:x=17
Step-by-step explanation:
Answer:
Step-by-step explanation:
We can let "a" stand for the number of goldfish Andrew has. Then the number Todd has is (70-a). We are told the difference is ...
a - (70-a) = 20
2a = 90 . . . . . . . .collect terms, add 70
a = 45
70-a = 25
Andrew has 45 goldfish; Todd has 25.
_____
<em>Comment on the problem</em>
I call this a "sum and difference" problem. You are given the total of two counts, and also their difference. If you were paying attention to the above solution, you see that <em>the larger of the counts</em> is (70+20)/2, <em>half the sum of the given numbers</em>. This is generically true of all <em>sum and difference</em> problems.
Knowing this, you can work most of these problems in your head.
Answer:
12 hours
Step-by-step explanation:
You have $12 in your bank and you need to get to $60 so
60-12= 48 , you need 48 dollars to reach to 60
48/4 = 12 hours. So if you get paid 4 dollars an hours, you only need to work 12 hours
Answer:0
Step-by-step explanation:
Because it is a 0