All categories

4 years ago

Find the area of the shape shown below 4 2 6 2 2 2

Mathematics

1 answer:

Vinil7 [7]4 years ago

3 0

Answer:

32 squared units

Step-by-step explanation:

The composite given in the figure consist of 3 triangles and 1 square shape.

To calculate the area of the composite shape, let's calculate area of each shape and then add all together.

==>Area of the square (Q): s²

s = 2

Area = 2² = 4 squared units

==>Area of biggest triangle (B): ½*b*h

b = 2+2+6 = 10

h = 4

Area = ½*10*4 = 5*4 = 20 squared units

==>Area of medium triangle (M): ½*b*h

b = 2

h = 6

Area = ½*2*6 = 6 squared units

==>Area of smallest triangle (S): ½*b*h

b = 2

h = 2

Area = ½*2*2 = 4/2 = 2 squared units

==>Area of composite shape = Q+B+M+S = 4+20+6+2 = 32 squared units

You might be interested in

Bus stop Restaurant sell 3/4 as many cheeseburgers as they do with hamburgers on any given day. If there are a total of 42 burge

schepotkina [342]

Answer:

24cb 18 hb

Step-by-step explanation:

Let's call C the number of cheese burger sold and H the number of hamburgers.

As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:

C= (3/4)H (equation 1)

The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:

C + H = 42

Replacing C by its value of eq. 1:

(3/4)H + H = 42

(3/4)H + (4/4)H = 42

(7/4) H = 42

Dividing both sides by (7/4)

H = 42/(7/4)

H= 42*(4/7)

H= (42/7)*4

H= 6*4

H=24

Then, C is:

C=(3/4)H

C=(3/4)*24

C= 3*24/4

C=72/4

C=18

We can verify it summing C+H

C+H=24+18=42 verified!

6 0

3 years ago

Vicky ran 5⁄14 of a mile and walked 1⁄7 of a mile. how much further did vicky run than walk?

raketka [301]

To solve, we need to subtract from these two fractions. In order to do this, we will change one of them to have the same denominator as the other.

We have 5/14 and 1/7
Let us change 1/7

Multiply 2/2 (a form of 1 so it does not change the value of the fraction)

2/2 • 1/7 = 2/14

Now subtract from 5/14
5/14 - 2/14 = 3/14

ANSWER: Vicky ran 3/14 of a mile more

7 0

3 years ago

B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =

jolli1 [7]

I suppose you mean

$g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)$

Differentiate one term at a time.

Rewrite the first term as

$\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}$

Then the product rule says

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'$

Then with the power and chain rules,

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}$

Simplify this a bit by factoring out $\frac12 (36-x^2)^{-3/2}$ :

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}$

For the second term, recall that

$\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}$

Then by the chain rule,

$\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}$