Assuming that 10% is the probability of a switch being defective (since left-handedness has nothing to do with the problem):
For a binomial distribution, probability(r out of n) = (nCr) (p)^r (q)^(1-r)
p = 10% = 0.1, q = 1 - p = 0.9
r = 2 switches, n = total of 12 switches
probability = (12C2) (0.1)^2 (0.9)^(12-2)
probability = 66(0.1)^2 (0.9)^10
probability = 0.23
Answer:
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Answer:
is 9
Step-by-step explanation:
9 x 9 = 81
Answer:
1. According to the angle bisector theorem, DAC = BAC
2. Same kind of goes for BC
3. X must be equal in both equations. x= 3
9(3) -7 = 20
4(3) +8 = 20
Hope this helped!