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iogann1982 [59]
3 years ago
9

Solve the equation (2^2x)/( 2^x+5) = 1 algebraically using two different initial steps as directed below.

Mathematics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

Given equation as:

\frac{2^2x}{2^{x+5}} = 1

now,

writing each side as power of 2

2⁰ = 1

therefore,

\frac{2^2x}{2^{x+5}} = 2⁰

also, we know the property that , when the number having the same bases gets divided , the powers of the number gets subtracted

therefore,

2^{2x-(x+5)}  = 2⁰

now for the equality the power of 2 both sides should be equal

thus,

⇒ 2x-(x+5) = 0

or

⇒ 2x = x + 5

or

⇒ 2x - x = 5

or

⇒ x = 5

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Natasha_Volkova [10]

Answer:

1. the Equation of vertical line=> x=3

2. the Equation of horizontal line

=> y = 4

5 0
2 years ago
What is the slope of a line that is perpendicular to the line shown.
sertanlavr [38]

Answer:

3/4

Step-by-step explanation:

First of all, we need to calculate the slope of the line shown. This can be computed as:

m=\frac{\Delta y}{\Delta x}

where

\Delta y = y_2-y_1 is the increment along the y-direction

\Delta x = x_2 - x_1 is the increment along the x-direction

We can choose the following two points to calculate the slope of the line shown:

(-3,2) and (0,-2)

And so, the slope of the line shown is

m=\frac{-2-(2)}{0-(-3)}=-\frac{4}{3}

Two lines are said to be perpendicular if the slope of the first line is the negative reciprocal of the slope of the second line:

m_2 = -\frac{1}{m_1}

Using m_1 = -\frac{4}{3}, we find that a line perpendicular to the line shown should have a slope of

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5 0
3 years ago
AGGGGGGGG!!! I'm so bad at math!! HELLLPPPLL
AlekseyPX
The correct answer is B. Hope it helps!
8 0
3 years ago
ASAP need answer to this system of equations... ILL give brainliest to correct answers only
pshichka [43]

Answer:

(7,12),(-12,-7)

Step-by-step explanation:

x^2 + y^2 = 193

x - y = - 5

x = y - 5

(y - 5)^2 + y^2 = 193

y^2 - 10y + 25 + y^2 = 193

2y^2 - 10y + 25 = 193

2y^2 - 10y + 25 - 193 = 0

2y^2 - 10y - 168 = 0

2*(y^2 - 5y - 84) = 0     This factors into

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3 years ago
What is the tru solution to the logarithmic equation below? Log4[log4(2x)]=1
zaharov [31]

\log_4(\log_42x)=1

Take both sides as powers of 4:

4^{\log_4(\log_42x)}=4^1\implies\log_42x=4

Do it again:

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3 0
3 years ago
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