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3 years ago

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Marcus plots the point (4, 7) in Quadrant I on the coordinate plane. Nicole then plots the point (4, –3) in Quadrant IV of the s

ame graph. Explain what the line that goes through those two points would look like, and evaluate the slope. Please do not type the sample response.

1 answer:

butalik [34]3 years ago

3 0

Answer:

d

Step-by-step explanation:

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BRAINLIESTT ASAP! PLEASE HELP ME :)

docker41 [41]

Answer:

The answer is A.

Step-by-step explanation:

The first graph was dilated by 1/2, therefore the answer is A

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3 years ago

Read 2 more answers

What is the value of the expression 12÷(−32)×7?

nadezda [96]

Answer:

Step-by-step explanation:

$\frac{12}{(-32)} \\$ ×7 = $-\frac{21}{8}$

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3 years ago

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of

iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is $\\ P(z>0.48) = P(x>533.2) = 0.3156$

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a <em>sample mean</em>. The distribution for <em>sample means</em> follows a <em>normal distribution</em> with mean $\\ \mu$ and standard deviation $\\ \frac{\sigma}{\sqrt{n}}$ . Mathematically

$\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

For values of the sample $\\ n \ge 30$ , no matter the distribution the data come from.

And the variable <em>z</em> follows a <em>standard normal distribution</em>, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [1]

That is

$\\ z \sim N(0, 1)$

We have a variance of 3364. That is, a <em>standard deviation</em> of

$\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58$

The population mean is

$\\ \mu = 530$

The sample size is $\\ n = 75$

The sample mean is $\\ \overline{x} = 533.2$

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}$

$\\ z = \frac{3.2}{\frac{58}{8.66025}}$

$\\ z = \frac{3.2}{6.69726}$

$\\ z = 0.47780$

With this value of z we can consult a <em>cumulative standard normal table</em> (or use some statistic program) to find the cumulative probability for <em>z</em> (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

$\\ P(z$

However, in the question we are asked for $\\ P(z>0.48) = P(x>533.2)$ . As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

$\\ P(z>0.48) = 1 - P(z$

Thus

$\\ P(z>0.48) = 1 - 0.68439$

$\\ P(z>0.48) = 0.31561$

Rounding to four decimal places, we have

$\\ P(z>0.48) = 0.3156$

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) $\\ P(z>0.48) = P(x>533.2) = 0.3156$ .

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4 years ago

What is the quotient of 3/4 5/6

Advocard [28]

24 I just did this that’s the common denominator

7 0

3 years ago

Please someone help me!!! its urgent!

I am Lyosha [343]

Answer:

<em>12.99</em>

Step-by-step explanation:

<em>a²+b²=c²</em>

<em>a²+b²=c²√91²+√78²=c²</em>

<em>a²+b²=c²√91²+√78²=c²√8281+√6084=c²</em>

<em>a²+b²=c²√91²+√78²=c²√8281+√6084=c²91+78=c²</em>

<em>a²+b²=c²√91²+√78²=c²√8281+√6084=c²91+78=c²169=c²</em>

<em>a²+b²=c²√91²+√78²=c²√8281+√6084=c²91+78=c²169=c²c=√169</em>

<em>a²+b²=c²√91²+√78²=c²√8281+√6084=c²91+78=c²169=c²c=√169 =13</em>

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2 years ago