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Lerok [7]
3 years ago
10

For the function k(x) =Negative StartFraction 1 Over 16 EndFraction x – 8, what is the inverse function k–1(x)?

Mathematics
2 answers:
Zolol [24]3 years ago
8 0

Answer:

Step-by-step explanation: it’s D on edge

lord [1]3 years ago
8 0

Answer:

It is k^-1(x)=-16(x+8)

Step-by-step explanation:

Flip the fraction to its reciprocal and opposite. Opposite of x-8 as well. When doing inverse basically do opposite of everything. Hope this helps

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great how much to get your car washed

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5 0
3 years ago
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Katrice wrote the numbers 137 and 174. Which sentence is true about the digit 7 in each number?
marshall27 [118]

Answer:

The 7 in 137 represents ten times the 7 in 137 (the second option)

Step-by-step explanation:

The seven in 137 equals 7

The seven in 174 equals 70

7 times 10 = 70

I hope this helped!

5 0
3 years ago
Which strategy best explains how to solve this problem? Rebecca bought a meal and two snacks for lunch each day. The meal cost $
Fittoniya [83]
Given:
Cost of lunch per day = 1 meal and 2 snacks

C = 5.5 + 2(0.75) = 5.5 + 1.5 = 7

7 * 12 days = 84

Based on the choices, the best strategy would be:

<span> A. Make a table. Write the numbers 1 to 12 in the top row of the table (the number of days). In the first box on the second row, write $7. This is how much Rebecca spends in 1 day. In each of the next boxes in the second row, write the amount Rebecca spends by adding $7 to the previous amount. The answer in box 12 is the total amount Rebecca spent after 12 days.</span>

6 0
3 years ago
can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylind
shutvik [7]

the new radius be to meet the client's need is 4.9 cm .

<u>Step-by-step explanation:</u>

Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:

Let we have two cylinders of volume V_1 , V_2 with parameters as follows :

r_1=6cm\\h_1=10cm\\r_2=?\\h_2=15cm

We know that volume of cylinder is \pi r^2h , According to question volume of both cylinder is equal i.e

⇒ V_1=V_2

⇒ \pi (r_1)^2h_1= \pi (r_2)^2h_2

⇒ (r_1)^2h_1= (r_2)^2h_2

⇒ \frac{(r_1)^2h_1}{h_2}= (r_2)^2

⇒ (r_2) =\sqrt{ \frac{(r_1)^2h_1}{h_2}}                   Putting all values

⇒ (r_2) =\sqrt{ \frac{(6)^2(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{36(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{360}{15}}

⇒ (r_2) =\sqrt{24}

⇒ (r_2) =4.9cm

Therefore , the new radius be to meet the client's need is 4.9 cm .

7 0
3 years ago
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Temka [501]

The answer is x<20. Hope that helps.

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4 years ago
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