All categories

2 years ago

(05.03)An irregular polygon is shown below:

Mathematics

1 answer:

SVEN [57.7K]2 years ago

7 0

9units sorry for not showing work though but glad I can help

You might be interested in

Rewrite each expression in the form kkxxnn, where kk is a real number and nn is an integer. Assume x ≠ 0.

labwork [276]

Answer:

The expression will be $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Step-by-step explanation:

We have given the expression $2x^5\times x^{10}$

We have to write this expression in kkxxnn form , here kk is real number and nn is integer

We know the property of exponent that when two function are multiplied thn their exponent are added

So $2x^5\times x^{10}=2x^{5+10}=2x^{15}$

Here kk = 2 and nn = 15

7 0

2 years ago

Helpppppp I’m marking brainliest

snow_tiger [21]

Answer:

So it's 1/6x2/3 which is 0.111111 in decimal since on there I can see you can't submit it in fractions! :D

Step-by-step explanation:

6 0

2 years ago

Rachel is saving money to buy an outfit for a party she has already saved $17 she is earning $5 each month for being a mother's

AveGali [126]

Answer:

18 Weeks

Step-by-step explanation:

$39.50=17 + (5*x)

$39.50-17=17-17 + (5*x)

$22.5/5=(5*x)/5

It will take 4.5 months to save up. If each month has 4 weeks it will take 18 weeks

7 0

2 years ago

Which equation represents the graphed function?

gtnhenbr [62]

Answer:

the answer is A.

Step-by-step explanation:

the slope is 4 and the y-intercept is -2

4 0

3 years ago

Read 2 more answers

Lance Rice has decided to invest $1,200 quarterly for eight years in an ordinary annuity at 4%. The total cash value of the annu

Likurg_2 [28]

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]
\\\\$

$\bf \begin{cases}
A=
\begin{array}{llll}
\textit{original amount}\\
\textit{already compounded}
\end{array}\begin{array}{llll}\end{array}\\
pymnt=\textit{periodic payments}\to &1200\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, meaning }
\end{array}\to &4\\

t=years\to &8
\end{cases}
\\\\\\
A=1200\left[ \cfrac{\left( 1+\frac{0.04}{4} \right)^{4\cdot 8}-1}{\frac{0.04}{4}} \right]$

6 0

2 years ago