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alukav5142 [94]
2 years ago
8

You can use a minus sign to make a negative numberlike -2. What happens to each of the following 2++2

Computers and Technology
1 answer:
Nostrana [21]2 years ago
6 0
2 - -2 = 4
2 + -2 = 0
2 - +2 = 0
:)
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Rose has a list of two columns of information separated by tabs. She wants to input this information into a table. What is the f
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I gotchu my bro!!
it would be D. " clicking Convert Text to Table"
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3 years ago
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Write a function `has_more_zs` to determine which of two strings contains # more instances of the letter "z". It should take as
nekit [7.7K]

Answer:

// Method's name: has_more_zs

// Parameters are text1 and text2 to hold the two phrases to be tested

public static String has_more_zs(String text1, String text2) {

 // Create and initialize z1 to zero

 // Use z1 to count the number of zs in text1

 int z1 = 0;

 // Create and initialize z2 to zero

 // Use z2 to count the number of zs in text2

 int z2 = 0;

 

 //Create a loop to cycle through the characters in text1

 //Increment z1 by one if the current character is a 'z'

 int i = 0;

 while (i < text1.length()) {

  if (text1.charAt(i) == 'z' || text1.charAt(i) == 'Z') {

   z1 += 1;

  }

  i++;

 }

 //Create a loop to cycle through the characters in text2

 //Increment z2 by one if the current character is a 'z'

 

 i = 0; //Re-initialize i to zero

 

 while (i < text2.length()) {

  if (text2.charAt(i) == 'z' || text2.charAt(i) == 'Z') {

   z2 += 1;

  }

  i++;

 }

 

 

 //Using the values of z1 and z2, return the necessary statements

 if (z1 > z2) {

  return "The phrase '" + text1 + "'" + " has more occurences of z than the phrase " + "'" + text2 + "'";

 }

 else if (z1 < z1) {

  return "The phrase '" + text2 + "'" + " has more occurences of z than the phrase " + "'" + text1 + "'";

 }

 else if (z1 == z2) {

  return "The strings have the same number of z";

 }

 else {

  return "Neither string contains the the letter z";

 }

}

Explanation:

Explanation to answer has been given in the code as comments. Please refer to the comments for the details of the code.

The source code file has been attached to this response and saved as "NumberOfZs.java"

Hope this helps!

Download java
5 0
3 years ago
Compare Fibonacci (recursion vs. bottom up)
ipn [44]

Answer:

C++ code explained below

Explanation:

#include<bits/stdc++.h>

#include <iostream>

using namespace std;

int FiboNR(int n)

{

int max=n+1;

int F[max];

F[0]=0;F[1]=1;

for(int i=2;i<=n;i++)

{

F[i]=F[i-1]+F[i-2];

}

return (F[n]);

}

int FiboR(int n)

{

if(n==0||n==1)

return n;

else

return (FiboR(n-1)+FiboR(n-2));

}

int main()

{

long long int i,f;

double t1,t2;

int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};

cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;

cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;

for(i=0;i<16;i++)

{

clock_t begin = clock();

f=FiboR(n[i]);

clock_t end = clock();

t1=double(end-begin); // elapsed time in milli secons

begin = clock();

f=FiboNR(n[i]);

end = clock();

t2=double(end-begin);

cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds

}

return 0;

}

7 0
3 years ago
Given the following function definition
siniylev [52]

Answer:

B. 1 6 3

Explanation:

Given function definition for calc:

void calc (int a, int& b)

{

int c;

c = a + 2;

a = a * 3;

b = c + a;

}

Function invocation:

x = 1;

y = 2;

z = 3;

calc(x, y);

cout << x << " " << y << " " << z << endl;

  • Since x is passed by value, its value remains 1.
  • y is passed by reference to the function calc(x,y);

Tracing the function execution:

c=3

a=3

b=c+a = 6;

But b actually corresponds to y. So y=6 after function call.

  • Since z is not involved in function call, its value remain 3.

So output: 1 6 3

3 0
3 years ago
Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Gnoma [55]

Answer:

public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

       }

       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

Explanation:

Using Java prograamming Language.

The Method (function) print_popcorn_time is defined to accept a single parameter of type int

Using if...else if ....else statements it prints the expected output given in the question

A complete java program calling the method is given below

public class num6 {

   public static void main(String[] args) {

       int bagOunces = 7;

       print_popcorn_time(bagOunces);

   }

   public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

       }

       else if(bag_ounces>10){

           System.out.println("Too Large");

       }

       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

}

3 0
3 years ago
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