3517 is a prime number. What else are you looking for?
Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
The ratio of cm to mi is 1/30, and we are looking for x/110. Since 1/30 = x/110, 30x=110.
x = 110/30 = 11/3 = 3.7 cm
Answer:
1. No
2. No
3. No
4. No
Step-by-step explanation:
y=2 so you multiply your x by 2 and you should come out with your y
your y should be 1 * 2 = 2 but is 9 ---->for (1, 9)
your y should be -6 * 2 = -12 but is 2 ---->for (-6, 2)
your y should be 2 * 2 = 4 but is -8 ----->for (2, -8)
your y should be 0 * 2 = 0 but is -4 ----> ( 0, -4)
side note -I'm sorry if you get it wrong,hopefully it's right though.