Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
When you separate them
Solve them separately:
Remove the denominators:
Find GCF (Greatest Common Factor):
Answer:
7 cm
Step-by-step explanation:
SA = 208 cm^2
SA= 2*a*b + 2*a*c + 2*b*c
where:
a= first dimension = 2 cm
b= second dimension = 10 cm
c= third dimension
so we have:
208= 2*2*10 + 2*2*c + 2*10*c
208= 40 + 4c + 20c
208-40= 24c
168=24c
c =168/24
c = 7cm = third dimension
Answer:
3/4
Step-by-step explanation:
Rise over run.
Go up 3 units and 4 units to the right to find the next point
