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azamat
2 years ago
6

Ashley has 100 books that she wants to give away at the rate of n books per week. Write a recursive function that represents the

number of books Ashley has at any time. The recursive function that gives the number of books Ashley has at any time is ____=______, started at ____.
Mathematics
1 answer:
laila [671]2 years ago
6 0

Answer:

Total number of books = 100

Number of books Ashley had given away after first week= n

Number of books Ashley had given away after second week= 2n

Number of books Ashley had given away after w week= wn

Books = Total - Number of Books she will give away

Books = 100 - wn

Step-by-step explanation:

hope this helps

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I don’t understand please put it in a form i could possibly understand
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3 years ago
I need h e l p !!!!!!!!!!!!!!!!
Strike441 [17]

Answer:

  • 3/ 23765

Step-by-step explanation:

There are 12 E's out of 100 tiles.

Tiles are not replaced.

<u>The probability of each of first 4 E's is:</u>

  • The first E ⇒ P(E) = 12/100 = 3/25
  • The second E ⇒ P(E) = 11/99 = 1/9
  • The third E ⇒ P(E) = 10/98 = 5/49
  • The fourth E ⇒ P(E) = 9/97

<u>The probability of 4 E's is:</u>

  • P(4 E's) = 3/25*1/9*5/49*9/97 = 3 / (5*49*97) = 3 / 23765

3 0
3 years ago
Judah's family wants to ride the bumper boats at a water park. There are 4 children (c) and 2 adults 9 (a) in Judah's family. Th
zhannawk [14.2K]

Answer:

Yes, the boats are safe to ride.

Step-by-step explanation:

40 (4) + 12 (2) ≤ 500

160 + 24 ≤ 500

184  ≤ 500

184 is less than 500.

because I was not sure if you had 9 adults instead of 2, this is the answer:

40 (4) + 12 (9) ≤ 500

160 + 108 ≤ 500

268 ≤ 500

268 is less than 500

3 0
3 years ago
Read 2 more answers
Many elementary school students in a school district currently have ear infections. A random sample of children in two different
Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school n_1 = 42

sample size for the second school n_2  = 34

so 16 out of 42 i.e x_1 = 16 and 18 out of 34 i.e x_2 = 18 have ear infection.

the proportion of students with ear infection Is as follows:

\hat p_1 = \dfrac{16}{42} = 0.38095

\hat p_2 = \dfrac{18}{34}  =  0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}

\bar p = \dfrac{16 +18}{42 +34}

\bar p = \dfrac{34}{76}

\bar p = 0.447368

\bar p + \bar  q = 1 \\ \\ \bar q = 1 -\bar  p \\  \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632

The pooled standard error can be computed by using the formula:

S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} +  \dfrac{\bar p \bar p}{n_2} }

S.E = \sqrt{ \dfrac{  0.447368 *  0.552632}{ 42} +  \dfrac{ 0.447368 *  0.447368}{34} }

S.E = \sqrt{ \dfrac{  0.2472298726}{ 42} +  \dfrac{ 0.2001381274}{34} }

S.E = \sqrt{ 0.01177284105}

S.E = 0.1085

The test statistics is ;

z = \dfrac{\hat p_1 - \hat p_2}{S.E}

z = \dfrac{0.38095- 0.5294}{0.1085}

z = \dfrac{-0.14845}{0.1085}

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0
3 years ago
Anyone mind helping?
elena-s [515]

Answer:

15 x^8 y^3

Step-by-step explanation:

The area of a rectangle is given by

A = l*w  where l is the length and w is the width

A = ( 5x^6 y^2) *( 3x^2 y)

   = 15 x^(6+2) y^(2+1)

   = 15 x^8 y^3

4 0
2 years ago
Read 2 more answers
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